Recent content by Psyguy22

So I just solve dy/dt= -.1 when t=0 and that should give me my k?

1 the problem and all known variables. A person is murdered in a room with a temperature of 20 deg C. At the time the body is discovered, the body temp is 32 deg C and is decreasing at an instantaneous rate of .1 deg C/minute. How long ago was the murder commited? 2. Related equations...

I was just wondering if there's a way to measure pain. I figured it'd be and equation like current. Like voltage would be the amount of pain, ohm would be a persons resistance to pain, and current would be the pain they actually felt.

We know that there are force carrying particles for the strong and weak nuclear force, and the electromagnetism force. But in Einsteins theory of relativity, he states that gravity is the bending of space time, not a force. So if there is no force, why do we say there must be a graviton? Ps I'm...

Ok i fixed the two mistakes, but I'm still coming up with the wrong answer. I think I have something wrong with the peiod but am unsure how to fix it

Homework Statement When a mass is attached to a vertical spring, the spring is stretched a distance d. The mass is then pulled down from this position and released. It undergoes 57 oscillations in 39.0 s. What was the distance d? Homework Equations F=-Kx F=mg T=2pi*sqrt(K/m) The...

Thank you. The answer was looking for you to say that 113km was the distance between the center of the asteroid.

@ D H I see... I don't know why I have the sqrt in the g equation... But even so, I'm getting .01127 m/s^2 and its still wrong. @rude man I haven't used the same R.. I used 1323000 m for the top R and 19300 for the bottom R

Ok so for units I'm getting sqrt(m)/s... which I have no idea what that means...

For r1 I have .121+.353+.121 which is .595 m for r2, it's just .242 m

That's 19.3 km in m. So I get g= sqrt((4π^2*(132300)^3)/(19300^2 * 147600^2)) (132300m is 19.3km+113km.) Which comes to .106 m/s^2, but it still says its the wrong answer.

Homework Statement Two identical 28.5-kg spheres of radius 12.1 cm are 35.3 cm apart (center-to-center distance) and at rest in outer space. (You can assume that the only force acting on each mass is the gravitational force due to the other mass.) a) If they are released from rest and...

I have (4 π^2 (19300m+113000m)^3)/((6.674*10^(-11)) (147600s)) which came out to be 6.28753*10^(16) kg So then I have g=sqrt(G M/R^2) or g=sqrt((6.674*10^(-11)) (6.28753*10^(16)))/ (19300^2) Which came out to be 14.74 m/s^2 (sorry about the exponents being...

Ok. So I put the numbers in and got a mass of 6.2875... E16. So then using the second equation I came up with 14.74 m/s^2 which is totally unreasonable for and asteroid that small. I changed all the kilometers to meters so the units all go together, so I'm not sure where I went wrong.

Homework Statement An asteroid is discovered to have a tiny moon that orbits it in a circular path at a distance of 113 km and with a period of 41.0 h. The asteroid is roughly spherical (unusual for such a small body) with a radius of 19.3 km. a) Find the acceleration of gravity at the...