Recent content by Qwurty2.0

  1. Q

    Voltage across resistors in RC circuit

    Thanks, I was looking at the circuit wrong (I thought the charge was coming out the top and hitting the resistor after the capacitor). Is there a way to calculate the voltage of the capacitor as it is discharging from 5V?
  2. Q

    Voltage across resistors in RC circuit

    Homework Statement Calculate the voltage, current, and power across the two resistors for every second of run 1 in the RC circuit. The RC Circuit: The settings of the circuit: The Graph. The capacitor is charged until it reaches 5.0 V and then discharged until it reaches 1.0 V. This...
  3. Q

    Harmonic motion and Electrical Fields

    I'll fix my units. The answer for question (a) is correct according to the book solutions. EDIT: I misread the answer, it is 0.2 ps. So there is no problem (besides my units).
  4. Q

    Harmonic motion and Electrical Fields

    Homework Statement Two positive charges +Q are affixed rigidly to the x-axis, one at x = +d and the other at x = -d. A third charge +q of mass m, which is constrained to move only along the x-axis, is displaced from the origin by a small distance s << d and then released from rest. (a) Show...
  5. Q

    Coeff. of Linear Exp. of glass from vol expansion of content

    Ah, my mistake. I understand what I was doing wrong. Thank you.
  6. Q

    Coeff. of Linear Exp. of glass from vol expansion of content

    But if 20°C (293.15 K) is the initial temperature and the final temperature is Ti + ΔT = 20°C + 25°C = 293.15 K + 298.15 K = 591.3 K, and ΔT is Tf - Ti, then isn't ΔT = 591.3 K - 293.15 K = 298.15 K? What am I missing? Don't they give the change in temp right away? :(
  7. Q

    Entropy change of system two substances

    I calculate that ΔSSi = -72.939 J/K and ΔSHg = 77.697 J/K. Added them together, I got a net entropy change of 4.758 J/K.
  8. Q

    Entropy change of system two substances

    ΔS = ΔSH + ΔSL = -Q/THM + Q/TLM ΔSSi = - (85394.4 J)/(321.96 K) = -265.23 J/K ΔSHg = (33153.12 J)/(321.96 K) = 102.97 J/K ΔS = -265.23 J/K + 102.97 J/K = -162.26 Am I supposed to use the middle heat (321.96 K) to calculate the ΔQ for each substance (ΔTSi = 333.15 K - 321.96 K = 11.19 K and...
  9. Q

    Coeff. of Linear Exp. of glass from vol expansion of content

    I believe so. There is 1 significant figure (the 1 liter volume), so the answer I would have is 2x10-4. But the issue isn't the sig. figs. (at least I don't think), it's the exponent. My answer has 2x10-4, while the closest answer is 2x10-5. I've gone over my calculations and I believe I have...
  10. Q

    Coeff. of Linear Exp. of glass from vol expansion of content

    Homework Statement The coefficient of volume expansion of olive oil is 0.68 × 10-3 K-1. A 1-liter glass beaker is filled to the brim with olive oil at room temperature. The beaker is placed on a range and the temperature of the oil and beaker increases by 25 C°. As a result, 0.0167 liters of...
  11. Q

    Entropy change of system two substances

    Q = mSi * CSi * (333.15 K - HeatLost) Q = mHg * CHg * (HeatGained - 293.15 K) mSi * CSi * (333.15 K - HeatLost) = mHg * CHg * (HeatGained - 293.15 K) (3.00 Kg) * (711.62 J/(Kg⋅K)) * (333.15 K - x) = (6.00 Kg) * (138.138 J/(Kg⋅K)) * (x - 293.15 K) (2134.86 J/K) * (333.15 K - x) = (828.828 J/K) *...
  12. Q

    Entropy change of system two substances

    I assume it is (20°C + 60°C) / 2 = 40°C (313.15 K), being that no energy left the system in the process.
  13. Q

    Entropy change of system two substances

    Homework Statement A 3.00-kg block of silicon at 60.0°C is immersed in 6.00 kg of mercury at 20.0°C. What is the entropy increase of this system as it moves to equilibrium? The specific heat of silicon is 0.17 cal/(g·K) and the specific heat of mercury is 0.033 cal/(g·K). Homework Equations Q...
  14. Q

    Maxwell Distribution of speeds

    My bad, I calculated it wrong. I tried again and got the right answer. Thank you!
  15. Q

    Maxwell Distribution of speeds

    I did what you said: I squared the velocities, then I calculated the weighted average (same way as I did above), and then took the square root of the weighted average. I ended up getting 82914.03 m/s, which is close to the answer I originally got but not the correct answer. What am I missing?
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