Recent content by ramialsaiad

Homework Statement Hi I want to derive the equation of kinetic energy for a mass on two springs .. Here is the figure of the system: http://faculty.ndhu.edu.tw/~clcheng/class-98/gen-phy98/gen-phy98-1-Q2s.pdf Am I doing right for calculating the kinetic energy for the mass on two springs ...

I do not know how to do ? if you can provide the starting equation to me that will be nice ,, then I try to go further

simple harmonic motion

potential energy

no idea

potential energy and I got it correct as you said before

I have to find KE , it is required .. I do want to find the equation of motion in terms of x for KE and PE and the force on the brick as a function of x .. Iam sure it is moving in vertical direction ..

total energi = 1/2*m*(dx/dt)^2 + mgx +1/2*k*(x/sin(a) - L)^2 + 1/2*k*(x/sin(a) - L)^2 the kinetic energy is 1/2*m*(dx/dt)^2 ... Can we rewrite the kinetic energy equation in function of x instead of dx ?

the kinetic energy in function of x is : KE(x)= 1/2*m*v^2= 1/2*m*(dx/dt)^2 Is it correct now?

can you write the equation here ? thanks

Can you write the kinetic energy equation here?

We have two springs so the kinetic energy should be double as much ,, is not that? thanks

So you mean that this F(x) = k*(x/sin(a) - L) + k*(x/sin(a) - L) is correct ! and KE(x)= 1/2*m*v^2 + 1/2*m*v^2 = KE(x)= 1/2*m*(dx/dt)^2 + 1/2*m*(dx/dt)^2 Is it like that? thank you very much

Is that the force of the block in function of x is : F(x) = k*(x/sin(a) - L) + k*(x/sin(a) - L) and the kinetic energy in function of x is : KE(x)= 1/2*m*v^2 + 1/2*m*v^2 (I cannot express it in x) Is that correct ? thanks

thank you very much