Derive the kinetic energy of a mass on two springs

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SUMMARY

The discussion focuses on deriving the kinetic energy equation for a mass attached to two springs, utilizing the integral of force, ΔK = ∫ F(x) · dx. The user attempts to calculate kinetic energy using the formula ΔK = (-2kx^2)/2 + ∫ 2kxL/(√(x^2 + L^2)), but is advised to specify the limits of integration to determine the kinetic energy accurately. The importance of establishing a starting point where kinetic energy equals zero is emphasized for correct calculations.

PREREQUISITES
  • Understanding of classical mechanics principles, particularly kinetic energy.
  • Familiarity with Hooke's Law and spring constants (k).
  • Knowledge of integral calculus and its application in physics.
  • Ability to interpret and analyze physical diagrams related to spring systems.
NEXT STEPS
  • Study the derivation of kinetic energy in systems involving multiple springs.
  • Learn about the application of Hooke's Law in dynamic systems.
  • Explore integral calculus techniques for solving physics problems.
  • Investigate the effects of spring constants on the motion of mass-spring systems.
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone interested in the dynamics of mass-spring systems.

ramialsaiad
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Homework Statement


Hi

I want to derive the equation of kinetic energy for a mass on two springs .. Here is the figure of the system:
http://faculty.ndhu.edu.tw/~clcheng/class-98/gen-phy98/gen-phy98-1-Q2s.pdf

Am I doing right for calculating the kinetic energy for the mass on two springs ?

Homework Equations



ΔK = ∫ F(x) · dx

The Attempt at a Solution



My attempt to solve the kinetic equation is by using this formula :

ΔK = ∫ F(x) · dx

so ΔK = (-2kx^2)/2 + ∫ 2kxL/(√(x^2 + L^2)) = (-2kx^2)/2 + 2kL*√(x^2 + L^2)

Am I doing right for calculating the kinetic energy for the mass on two springs ?

Thanks
 
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Hi Ramialsaiad,

What are the limits for your integral?

You have to integrate between, say, x0 and x. To determine the actual KE at a given point you would need to start at the value for x0 where KE = 0.

AM
 

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