Recent content by Rasine

1. Kondo Lattice vs. Single Impurity Kondo System

In order for a dilute magnetic alloy to show the kondo effect (resistance minimum at low T), the magnetic impurites must be far apart and non-interacting. In the Kondo lattice, the magnetic impurities are much closer togeather (one impurity per unit cell), so why does this system show the...
2. Falling bodies

If two objects of equal mass are dropped....one from h1 and the other fro h2.....will they hit the ground with the same force? Because the only force acting on the objects is gravity so we can say: F=ma and the acceleration is constant...so the forces must be the same. Is this...
3. Au doped with Fe Spin Glass

Hello everyone, I am an undergratude student doing to research and I am making dirty Au films. At certian concentrations of Fe (say >.5%) this Au-Fe is showing charateristics of a sping glass. I am attempting to learn what exactly a spin glass is and what its trends look like (resistance vs...
4. C/++/# Sovling schrodinger's equation in C++

i need help coming up with a way to solve for the eigen vectors of schrodinger's time independant equation in c++. so i want to write a class that uses the shooting method, but i am not sure how to do that.
5. Determine the electric flux through each of the sides

right it is the first value...i don't have the notation for that in my keypad.... but the when i do that operation =2.37x10^5 N m^2/C which is wrong
6. Determine the electric flux through each of the sides

well the net charge inside is just 2.1x10^-6 C/e is that right?
7. Determine the electric flux through each of the sides

that means that the flux= the charge on the inside of the soild/ the constant e which is 8.85 x10^-12
8. Determine the electric flux through each of the sides

ohh thats right...ok so now if i calcuate what E is E=Kq/r^2 now r is at the the center of the cube so r=.064/2 E=(8.99x10^9)(2.1x10^-6)/.032^2=1.84x10^7 A=.064*.064=.004096 now 1/6flux=(1.84x10^7)(.004096) flux=4.53x10^5....but that still isn't the right answer help me please
9. Determine the electric flux through each of the sides

A 2.10- mC charge is placed at the center of a cube of sides 6.40 cm. Determine the electric flux through each of the sides. ok so electric flux=E(A) so i figure that the electic flux will be the same for all six sides of the cube so i am just calculating the flux on one side then X6...
10. Partial fraction decompostion

thank you very much
11. Partial fraction decompostion

ohhh ok...i think i understand.. so if i have (2x+3)/(x+1)^2=(A/x+1)+(B/(x+1)^2) (*) then 2x+3=A(x+1)+B cuz i multiply both sides by (x+1)^2
12. Partial fraction decompostion

so should it be 2x+3/(x+1)(x+1)=(A/x+1)+(B/x+1) here..i just split up the (x+1)^2 this is right?
13. Partial fraction decompostion

what happened to to (x+1)^2 term?
14. Partial fraction decompostion

(2x+3)/(x+1)^2 so this is what i am thinking...but it does not make sense =(A/x+1)+(B/(x+1)^2) so then 2x+3=A(x+1)^2+B(x+1) 2x+3=Ax^2+A2x+A+Bx+1 so that would make... 0=A 2=2A+B 3=A+B this solution does not make any sense becuase if A=0 then according to the second...
15. Charges on the vertex of a triangle

ummm...so do i have to find in they x and y compnents and all that sutff?