Alright, let's do this:
From 0 to 1 we have one function, and from 1 onward we have another. Split up our integral as so:
$$\int_0^1 e^{-st} e^{t}dt + \int_{1}^{\infty} e^{-st}(0)dt \implies \int_0^1 e^{t(1-s)}dt$$
Hi,
I'm asking this because I ordered this book today, but there is a 4-day shipping minimum. I have to do a few problems from this book, and if anyone owns this, is it possible to tell me the problem statements?
Also, if I'm not allowed to ask for this, please let me know.
The problems I...
Homework Statement
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Now, this problem is not the typical stars and bars problem. I'm actually trying to solve for this:
If I had n red marbles and m blue marble, I want the probability that I pick n red marbles and only 1 blue marble. The order is irrelevant, meaning, the only thing that is...
Well, ok.
Judging from your work, it seems as if you wanted to keep the time constant with respect to the first car to start. There's nothing wrong with this. However, if this is the case, your work is saying that the two cars will be meeting each other at different times with respect to the...
Hi,
Examining your given data, you are given a time rate of change, a half-life, and you want another time rate of change after a finite amount of time.
It looks like your first plan of action should be to find the initial amount of carbon-14 present, since that is a rather integral part of...
Hey there,
I think a really important concept that you might be forgetting is the principle of linearity with divisibility. Since your gcd divides both a+b and a-b, it is then also true that your gcd will divide ANY linear combination of these integers (assuming integer weights, of course)...
Hi,
I think the most convenient way to start is to imagine the triangle inequality for your boundary. As someone has pointed out already, what would the modulus for exp(ix) be? This will help because the largest modulus of z that you can find will also happen to be the largest modulus for...
The equations for impulse and momentum are what you want to use. Conservation of Momentum is probably what you meant to say.
Using conservation of momentum, you are given information that is pretty crucial, because you are told that the two shuttles are initially linked together. This means...