Recent content by roger12
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How Do You Solve Complex Ratio Problems in Chemistry?
So that leaves 5/8 of B and C which are in the ratio 1:2. Would then be: 3/8 of A, 5/8 of B and [ 5/8]/2 of C ?- roger12
- Post #4
- Forum: Precalculus Mathematics Homework Help
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How Do You Solve Complex Ratio Problems in Chemistry?
Homework Statement In each of the following the properties of a compound are given. In each case find A:B:C 1. 3/8 of A with B and C 1:2 2. A, B, C are mixed according to the ratios A:B=1:7 and B:C=13:9 Homework Equations The Attempt at a Solution I just can't seem to...- roger12
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- Ratio
- Replies: 4
- Forum: Precalculus Mathematics Homework Help
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I can't make sense of this log property explanation?
The parts in red mean x is less than or equal to 1. And it IS an equation : y=x^2+x+1: x< or =1 and y= 3-x : x>1 for [-3, 4] y is defined differently for different values of x. But both expressions are the parts of the same equation. The part of the graph defined by y= 3-x...- roger12
- Post #5
- Forum: Precalculus Mathematics Homework Help
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I can't make sense of this log property explanation?
Awesome! Why I forgot "If A=B^C, then C=log(base B)A" is beyond me.- roger12
- Post #4
- Forum: Precalculus Mathematics Homework Help
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I can't make sense of this log property explanation?
Homework Statement I decided to cram these two unrelated question into one post, because they are too small and I don't want to crowd the forum with my many little bitty questions. 1. log(base A) of B= 1/[log(base B) of A] because: if log(base B) of A=C, then B^C=A and so B=A^1/C...- roger12
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- Explanation Log Property
- Replies: 4
- Forum: Precalculus Mathematics Homework Help
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Rounding to required level of accuracy
It's Engineering Math by Stroud. It's a great book. Sometimes unexpected problems with strange answers pop up. These are some of the few.- roger12
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Rounding to required level of accuracy
Thank you for the answer. I tried to apply the rule that used for (b) to another problem and got another wrong answer. [4.62^2-(7.16-2.35)]/ [2.63+1.89* √(73.24)] The answer is 0.8793. I thought the answer had to be rounded to 3 sig fig.- roger12
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Rounding to required level of accuracy
Homework Statement Calculate each of the following to the required level of accuracy given that each number, other than those indicated in brackets, has been obtained by measurement. a) (3.142*1.95)/6*(3*5.44^2+1.95^2) (power 2, divisor 6, multiplier 3) b) (3.142*1.234)/12*(...- roger12
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- Accuracy
- Replies: 5
- Forum: Precalculus Mathematics Homework Help
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How do you solve ratio problems like these?
Thank you for the answers.- roger12
- Post #4
- Forum: Precalculus Mathematics Homework Help
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How do you solve ratio problems like these?
Homework Statement In each of the following the properties of a compound are given. In each case find A:B:C 1. 1/5 of A, 2/3 of B and the remainder of C. 2. 3/8 of A with B and C in the ratio 1:2. 3. A, B and C are mixed according to the ratios A:B= 2:5 and B:C=10:11. Homework...- roger12
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- Ratio
- Replies: 3
- Forum: Precalculus Mathematics Homework Help
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How Do You Simplify Complex Algebraic Expressions?
Thank You, Everyone.- roger12
- Post #4
- Forum: Precalculus Mathematics Homework Help
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How Do You Simplify Complex Algebraic Expressions?
Homework Statement Simplify the following, giving the result without fractional indices: [(x^2 -1)^2 * √(x+1)]/ (x-1)^3/2 Homework Equations The Attempt at a Solution There are no common bases to add the indices and no common indices to multiply out the bases so I tried this and...- roger12
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- Algebra
- Replies: 3
- Forum: Precalculus Mathematics Homework Help