How do you solve ratio problems like these?

  • Thread starter roger12
  • Start date
  • #1
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Homework Statement



In each of the following the properties of a compound are given. In each case find A:B:C

1. 1/5 of A, 2/3 of B and the remainder of C.

2. 3/8 of A with B and C in the ratio 1:2.

3. A, B and C are mixed according to the ratios A:B= 2:5 and B:C=10:11.

Homework Equations





The Attempt at a Solution



I could only solve the 1st one:

The common denominator is 15 so 15/3*2=10 and 15/5*1=3. That means A and B are in the ratio 3:10.

15/15-13/15=2/15 so A:B:C are in the ratio of 10:3:2

Couldn't solve the other two. Please, help. Thanks.
 

Answers and Replies

  • #2
uart
Science Advisor
2,776
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Ok in Q2 you know that the remainder (B and C) make up 5/8. Can you show how to split 5/8 in the ratio 1:2?
 
  • #3
103
2
Regarding Question 1:

I think you got the answer right but in the wrong order.

[itex]A:B:C[/itex]

[itex]\frac{1}{5}:\frac{2}{3}:\frac{x}{y}[/itex]

[itex](\frac{3}{15}:\frac{10}{15}:\frac{2}{15})*15[/itex]

[itex]3:10:2 == A:B:C[/itex]

Regarding Question 2:
You need the provided fraction to become large enough that it's remainder is evenly divisible into three parts.

Regarding Question 3:
A:B:C is what you're trying to build, so look at the ratios A:B and B:C as puzzle pieces.
A:B is too small to fit in with B:C, so you simply need to make A:B larger for it to be congruent with B:C
 
Last edited:
  • #4
12
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Thank you for the answers.
 

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