Recent content by SaltyBriefs

Homework Statement I'm trying to derive this formula, but I get stuck after I factor the t out. V_{f}^{2} = V_{0}^{2} + 2a (y-y_{0}) Homework Equations V_{f}^{2} = V_{0}^{2} + 2a (y-y_{0}) The Attempt at a Solution 1) y_{f} - y_{0} = (\frac{V_{0}+V_{f}}{2})t 2) y_{f} - y_{0}...

Let me know if you solved it, or if it helped. So I can get some personal feedback, because I don't want to be misinforming people lol.

Don't rely on measuring the displacement vector. Sometimes the ruler isn't as precise, also it will help you in the long run to have these equations in your tool box.

I would plug and chug for you, but I'm kind of confused by the bearings.

You can try other methods of finding vector C, you can find the components of vector A, and vector b Remember finding the magnitude or resultant vector is \vec{R} = \vec{A} + \vec{B} which is really \vec{R} = (A_{x} ) (B_{x} ) + (A_{y} ) (B_{y} ) A_{y} = (\vec{A}) (sin \theta)...

Beat me to it. But yeah do this.

Oh wait is this from cos, sin and since it is in the 4th quadrant, y is negative (sin) and x is positive (cos)

Thank you this helped so much! But um just a quick question, why is sin negative? O.o

Homework Statement Can vectors with 180+(degrees) have a negative magnitude? I'm trying to find components of a vector that is going 260 km, 48 (degrees) south of east. So I'm confused whether the 260 is positive or not because of the -48 degrees.Homework Equations (\vec{V}) (sin\theta)...

Homework Statement A plane leaves the airport in Galisto and flies 180 km at 68.0 (degrees) east of north and then changes direction to fly 260 km at 48.0 (degrees) south of east, after which it makes an immediate emergency landing in a pasture. Homework Equations Trig equations...