Calculate Horizontal Velocity of Jetliner at 233 m/s

[tryton]

Homework Statement

A jetliner is moving at a speed of 233 m/s. The vertical component of the plane's velocity is 66.9 m/s. Determine the magnitude of the horizontal component of the plane's velocity.

The Attempt at a Solution

233m/s^2=66m/s^2+x^2=233.189135m/s
66m/s cos(90)=0

I am not really sure how to find velocity from speed without knowing the angle... It's not given that it is 90... I know this is supposed to be easy but I am a beginner.

Thanks for help

 

[USN2ENG]

Homework Statement

A jetliner is moving at a speed of 233 m/s. The vertical component of the plane's velocity is 66.9 m/s. Determine the magnitude of the horizontal component of the plane's velocity.

The Attempt at a Solution

233m/s^2=66m/s^2+x^2=233.189135m/s
66m/s cos(90)=0

I am not really sure how to find velocity from speed without knowing the angle... It's not given that it is 90... I know this is supposed to be easy but I am a beginner.

Thanks for help

You are almost there:
So its Vx=Vcos(theta)

So then with algebra its: arccosine(Vx/V)=theta...plug in your given numbers..
Theta = 73.3 degrees

Then find the y component with Vy=Vsin(73.3) = 233sin(73.3)=223 so Vy=223m/s

to check this then you would do sqrt(Vx^2+Vy^2)=V

 

[SaltyBriefs]

You are almost there:
So its Vx=Vcos(theta)

So then with algebra its: arccosine(Vx/V^2)=theta...plug in your given numbers..
Theta = 73.3 degrees

Then find the y component with Vy=Vsin(73.3) = 233sin(73.3)=223 so Vy=223m/s

to check this then you would do sqrt(Vx^2+Vy^2)=V

Beat me to it. But yeah do this.

 

[tryton]

Thanks! That was helpful!