Recent content by SamTaylor

Ok, that way its pretty clear to me. I don't know why it didnt come to my mind that way right away. However the \lambda is still a bit confusion to me in the derivation. Looking at the quote above one could have written down the formula right away without the derivation.

That’s how I thought about it as well. I tried to think about it like in total probability. When you look at the picture above you can see the events S_n which compose the universal set. Like you said one can define a smaller set A which comprises outcomes in some or all of the events S_1...

Hi, I try to teach myself Hidden Markov Models. I am using this text "www.cs.sjsu.edu/~stamp/RUA/HMM.pdf" as Material. The Introduction with the example was reasonable but now I have trouble in unterstanding some of the derivation. I can follow the math and use the formulas to get...

Ok, the last post was nonsense... sorry

P(K_m) = P(J_n)*P(K_m|J_1) + P(J_n)*P(K_m|J_2) + P(J_n)*P(K_m|J_3) P(K_1) = 0.10 + 0.07 + 0.10 = 0.27 P(K_2) = 0.06 + 0.15 + 0.15 = 0.36 P(K_3) = 0.12 + 0.05 + 0.20 = 0.37 a) P(J_1|K_1) = \frac{P(J_1)*P(K_1|J_1)}{P(K_1)} = \frac{0.10}{0.27} = 0.37 P(J_2|K_2) =...

I thought about that but how do i get P(K) or P(J) ?

Homework Statement A Communication system transmits signals labeled 1, 2, and 3. The probability that symbol j is sent and symbol k is received is listed in the table for each pair (j,k) of sent and received symbols. For example, the probability is 0.12 that a 1 is sent and, owning to...

Homework Statement A chip contains twenty identical transistors, which are connected in such a way that the chip will perform its function provided that no more than three of the transistors have failed. The probability that any given transistor has failed equal 0.1. Calculate the...

Oh i think i found the mistake! \frac{P_a (1-P_b)}{1-(1-P_b)(1-P_a)} Which looks right to me, because when Pa goes higher, P(nb>na) -> Pb

with the help of \sum_{n=0}^{\infty} q^n = \frac{1}{1-q} P(b > a) = \sum_{n_a}^{\infty} \sum_{n_b=n_a+1}^{\infty} P(a_n,a_b) = 1-P_b is this correct ?

> Then you better go back and review basic probability. I already did. I guess here is some point i don't understand. So is the first assumption i did for P(n_a,n_b) also wrong?

> What's the probability P(n_A,n_B) of outcome (n_A,n_B)? P(n_a,n_b) = P_a*(1-P_a)^{(n_a-1)}*P_b*(1-P_b)^{(n_b-1)} > Finally, the event you're interested in consists of the outcomes where n_B>n_A. > How would you express that in terms of the probabilities of the individual outcomes? I have...

Hi I am having some problems solving this exercise. Can somebody give a hint on how to solve this. The hint from the book is not really helping me. Homework Statement Two sharpshooters, A and B, are going to shoot at a target. A has probability Pa of hitting it on a single shot; B has...

Thanks

I am reading a research paper about "narrow" autocorrelation and at the beginning there is an expression I don't unterstand http://www.wellesley.edu/Physics/brown/pubs/acv85_P1595-P1601.pdf" Does someone know what is meant with the word cross term?