Recent content by Samurai Weck

That's where I'm scratching my head. It can't be 38 and 31 m, because that's ridiculously low. It would have to be something that divides evenly into both. Or the fact that 7 m is separated between the two is also significant. Ah ha! So, since the difference between them is 7 m, that would...

Well, if they arrive at different points at the same time, they would have to be different wave fronts, because they're different distances. Also, the problem says the crest of the wave passes both listeners simultaneously.

The distance between one peak to another. I still don't see how you would use the two different lengths. Are each of the lengths representative of the two different frequencies?

Homework Statement A loudspeaker at the origin emits sound waves on a day when the speed of sound is 340 m/s. A crest of the wave simultaneously passes listeners at the coordinates (38,0) and (0,31). What are the lowest two possible frequencies of the sound? Honestly, I am most...

Actually, the unit they want mass in is g. Sorry. Forgot to put that in there.

Homework Statement A 1.50-m-long string is under 30.0 N of tension. A pulse travels the length of the string in 50.0 ms. Homework Equations v of string = sq rt of (Tension of string/ string's mass-to-length ratio) string's mass to length ratio= m/LThe Attempt at a Solution So, the pulse...

Ah, disregard my question. I was mistaken when I thought that pressure in p=nRT comes out in atm. It actually is in Pa and you have to change 3.46x10^7 to 3.46x10^4.

Ok, so I'm doing this homework online and I THINK I'm doing it correctly, but I'm getting incorrect answers. Homework Statement 0.290 mol of argon gas is admitted to an evacuated 40.0 cm^3 container at 60.0 degrees C. The gas then undergoes an isochoric heating to a temperature of 300...

Ooooooh. K=(1/2)Iw^2 w(omega) = 140rpm(1min/60sec)(2pi/rotation)=14.66 rad/s Krot= (1/2)(.024kgm^2)(14.66 rad/s)^2 = 2.53 J Thanks A LOT. This was the one problem out of my homework that was kicking my behind.

KE= (1/2)mv^2

I have a similar problem to this. The numbers are slightly different, though. A 260 g ball and a 510 g ball are connected by a 37.0-cm-long massless, rigid rod. The structure rotates about its center of mass at 140 rpm. What is its rotational kinetic energy? Well, I know I will need to...