Recent content by sawhai

Shouldn't I have the heating value of coal in order to find the amount of coal?

Thank you

I am sorry this comes from my bad background in chemistry, I get scared whenever feel that chemistry is involved! So the total electricity generation in a year is 600MW*365*24*3600= 18.9216*10^9 MW/year I am not sure how to calculate the mass of the coal and as used the efficiencies for the heat...

Thanks, Here is my calculation: C15H32+29.899 O2+112.42 N2=13.649 Co2 + 1.350 CO +7.574 O2+112.425 N2+ 15.998 H2O And for the theoretical air: C15H32+ 23 O2+ 86.48 N2=15 CO2+ 16 H2O+86.48 N2 AFR(theoretical) = (28.8*(23+86.48))/212 = 14.872 AFR(stoich) = (28.8*(29.899+112.42))/212 = 19.333...

True, So this answers the part (a) and (b) of the equation, correct?

I did this: Since the amount of N2 in the reactant has to be equal the amount of N2 in products, therefore and using the ratio of N2/O2 = 3.76 I set up two equations: x.y=5.6 (amount of O2); x = theoretical air and y = 1+excess air x(1+y) (3.76) = 83.278 (amount of N2) and I got x=16.568 and...

Do you think we should exclude H2O since the molar composition is given in dry basis?

I added the N2 to both equations: C5H32 + 13 O2 + 13.(3.76) N2 -->5CO2 + 16 H2O+48.88 N2 ------>complete combustion C5H32 + 10.5 O2+10.5.(3.76) N2 -->5CO2 +16 H2O+39.48 N2-------> Partial combustion Now how can I find out how much excess air was used and how much of the fuel was in complete and...

Homework Statement A fuel oil burned in a steam generator has a composition that may be represented as C15H32. A dry basis analysis of the flue gas yields the following molar composition: CO2 10.111%, CO 1.000%, O2 5.611%, and N2 83.278%. Determine the following: (a). The...

I was able to find the LHV of the coal in KJ/kmol. Now how can I use this value to find the kg of the coal in another word the LHV in KJ/kg without knowing the molecular mass of the coal?

Homework Statement A West Virginia coal burned in a steam generator has the following mass analysis: carbon 75.0%, oxygen 6.7%, hydrogen 5.0%, water 2.5%, sulfur 2.3%, nitrogen 1.5%, ash 7.0%. How much limestone, CaCO3, in kg/day is needed to remove 96% of the SO2 produced from combustion...

Thanks. Now another question An electron accelerated to 106 keV colides with another free electron and recoils. Its energy after the collision is 26 keV. (a) What is the energy of the other electron that was initially at rest? I said E=106-26=80keV (b)Assume the target electron is from the...

Ok, I think I now understand. Here is what I did: Gamma = E/mc^2 = 40GeV/6*931.5MeV = 7.15 t1/2 = t1/2 (Stationary)*gamma = 7.15*807ms Does this sound ok?

Homework Statement The question asks: "What is the half-life of a He-6 nucleus with total(kinetic+rest) energy E=40 GeV?" How can we approach this problem? Homework Equations E=mc2 ; The Attempt at a Solution I thought of getting the mass of the He-6 using M=E/c2...

Any one with an idea?