Recent content by Schniz2

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    Algebraic Manipulation: Solving Complex Equations

    ahh, finally got it... the last time i tried to do it that way i got and extra factor somehow and that's what was messing me up. thanks!
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    Algebraic Manipulation: Solving Complex Equations

    Homework Statement Somehow the upper two statements are manipulated to get the lower one but i can't work out how... (see attatched image) Homework Equations N/A The Attempt at a Solution Oh you don't want to see mypages of scribble. I can't get close to that expression!
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    Centre and Radius of Convergence

    I'm not really sure, the textbook seems to ignore the part containing the 'z' but this confuses me because it is to the power 'n' so i would have thought you would need to include it when finding the limit as 'n' goes to infinity. To make things more confusing our lecturer uses the ratio test...
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    Centre and Radius of Convergence

    sorry, was meant to be to the power 'n' and i had '2'
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    Centre and Radius of Convergence

    Homework Statement Find the centre and radius of convergence: \stackrel{\infty}{n=1}\sum n.(z+i\sqrt{2})^{n} Homework Equations 1) Ratio test \left|\frac{a_{n+1}}{a_{n}}\right|<1 2) Textbook uses \stackrel{lim}{n-> \infty}\left|\frac{a_{n}}{a_{n+1}}\right| The Attempt at a Solution using...
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    Confirm Hall Effect: Reversing Current & Magnetic Field

    Actually, i thought about it more and i think i finally kind of understand it... too messy to put into words but it sort of makes sense nickjer - the voltage offset eliminates the error due to misaligned voltage measurement probes.. you take one hall voltage measurement, reverse the magnetic...
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    Confirm Hall Effect: Reversing Current & Magnetic Field

    Homework Statement Show that the Hall voltage reverses sign if either the current or magnetic field direction is reversed, but the voltage offset reverses sign only if the current direction is reversed. Use the information to confirm the validity of equation see eq1 image Homework...
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    Is the Limit of Infinity Over Its Square Root Equal to 1?

    Cool, that worked well. And took forever. |H(jw)| = sqrt((RCjw)^2) / sqrt((RCjw)^2 +1) i need to estimate this as w -> infinity...
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    Is the Limit of Infinity Over Its Square Root Equal to 1?

    To be more precise, I am trying to to a Bode diagram for a simple circuit. I need to estimate |H(j\omega)| in decibels as \omega -> \infty and as \omega -> 0. The transfer function is |H(j\omega)| = \frac{\sqrt{\left(RCj\omega\right)^{2}}}{\sqrt{\left(RCj\omega\right)^{2}+1}}
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    Is the Limit of Infinity Over Its Square Root Equal to 1?

    Homework Statement \frac{\infty}{\sqrt{\infty}} I would have said it would be infinity because infinity would grow a lot faster than its square root wouldn't it? But my friend swears the limit is equal to 1?
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    How do I manipulate algebraic expressions?

    Thanks ;). Very clear to me now.
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    How do I manipulate algebraic expressions?

    Ahhh, i feel like such a fool for not seeing that. Thanks ;)
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    How do I manipulate algebraic expressions?

    Homework Statement As part of a calculus question, the solutions manual takes \frac{2y^{2}}{4+y^{2}} And somehow turns it into \left(2-\frac{8}{4+y^{2}}\right) Ive scribbled all the things i can thinkof on paper and still can't seem to get from one to the other, its driving me nuts...
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    Is y(t) Time-Invariant? Debating an Elementary Question

    The first proof is a bit heavy for me at this time of night... but the second seems to me that you have correctly proven it time variant. I'm no genius though... just letting you know i can't see any problem with your reasoning ;)
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