Thanks for the response gneill.
Ok, so if i need calculate a change in angle by one degree, i would use the equation of tan angle = sum of i/sum of j, and then arrange these values until i alter the angle by one degree.
That sound right guys?
Thanks, Sidge
Homework Statement
A rockets course needs to be diverted by one degree. The mass of the rocket is 2000kg, and its forward velocity is 15000ms. The rocket has side rockets with a thrust of 25000N with which to effect course change.
a) What is the rockets momentum after the course change...
so if u is infinitie that means its 1 right?
then my complete equation will be:
1/v = 1/f - 1/u
1/v = 1/0.8 - 1/1
1/v = 1/0.25
v = 4m
This seem right guys?? I am unsure as I am missing the moon subtending an angle of 0.5 degrees, which too be honest I am quite unsure about...
Because i have the focal point of 0.8, I am assuming that i should use the normal lens equation of 1/f = 1/u + 1/v which would be rearranged to 1/v = 1/f - 1/u because v = lens to image, so because I am after the size of the moons image on the screen this is what I am thinking is the correct...
A convex lens of focal point 0.8m focuses a real image of the moon onto a screen. If the moon subtends an angle of 0.5 degrees to an observer on earth, calculate the size of the moons image on the screen?
Thats the question guys, I am really struggling to find the appropriate equation as we...