Homework Statement
A chain lyinh on the ground is 10 m long and its mass 80 kg. How much work is required to raise one end of the chain to a height of 6m.
Homework Equations
W = F x d
= mg x d
W = integral of mg dx from 1 to 6
The Attempt at a Solution
since mass is 80 kg...
Yes I am 100% sure I am using the right integrel. The integral itself is odd and a longer and harder way to find the volume of this object. I would normally solve this in respect to x but the instrucotr wants it in respect to y.
And yeah I am 100% sure it is the right integrel
Homework Statement
2\pi \int_0^6 y\sqrt{25- (y- 1)^2}dy + 5\pi
That's the integral i need solved
2. The attempt at a solution[/b]
so first i subbed u=y-1
took the 2 pi out of the integral
that got me 2 integrals u*sqrt(25-(u)^2) du + sqrt(25-(u)^2) du
the first integral =...
2\pi \int_0^6 y\sqrt{25- (y- 1)^2}dy + 5\pi
that's the integral I want solved and the answer i got is (25pi^2)/2 + (500*pi)/3 intstead of 25pi^2 + 499.89pi/3
1. Homework Statement
k so here is the equation i need help with that will find me the volume of a sphere
2*pi*y*sqrt(25-(y-1)^2) dy - 5*pi from 0 to 6
the 5 pi is the volume of a cylinder
2. Steps
so first i subbed u=y-1
took the 2 pi out of the integral
that got me 2 integrals...
Homework Statement
sqrt(1 + x^4+ 2x^2)
Homework Equations
The Attempt at a Solution
k so i need a lead on this one, maybe some kind of substition, i am not quite adept with finding the integrals of a square root function with polynomials in it
Homework Statement
integral of x *sqrt( x/(x-1))
Homework Equations
The Attempt at a Solution
I honestly don't know how to approach this i don't see any type of trig substituions whatsover, I really need some kind of lead and an explnation y that method works