This is the simulator i used to obtain my data:
http://amrita.vlab.co.in/repo/PHY/MPY/Millikan-Oil-Drop/MillikansOilDrop_Simulation.html?linktoken=cae2f378fc729601e847e89adabd942e
Homework Statement
Hi, I had to calculate the charge of an oil drop using a lab simulation
Homework Equations
q = mgd/v
The Attempt at a Solution
This is the result i came up with:
The charges are not multiple of 1.6x10^-19 C. How can i fix this?
Thanks
The formula will be F = ILB SinƟ
This is what I get:
F = ILB sin 90
12 N = (7.0 A)(6.0 m)B sin 90
12 N/(7.0 A)(6.0 m) = B sin 90
2/7 = B sin 90
B = 2/7 T
B = 0.29 T
Homework Statement
1. Determine the magnetic force acting on an proton (m = 1.67 x 10-27 kg) moving at 2.9 x 106 m/s in a magnetic field of 6.8 T. The proton is moving south. The magnetic field points straight down.
2. A 6.0 m long wire with 7.0A of current flowing through it experiences a...
SammyS, after your suggestions I get the following answers:
1. Resultant = 0.19 N[19 degrees above horizontal]
2. Electric Field Strength: 2.9x10^2 N/C [WHAT WILL BE THE DIRECTION?]
3. Is this correct?
Pe = k(qa qb / rab + qa qc / rac + qb qc / rbc)
Pe = (9x10^9)(2x10^-6 * 4x10^-6 / 1...
Homework Statement
Given the following information:
Givens:
A = +2.0mC
B = +4.0 mC
C = - 4.0mC
All of the sides of the triangle are 1.0 m
The inside angles are 60°
1. Determine the force acting on charge C as a result of A and B. Be sure to include a direction.
2. Determine the...
For number 1:
sqrt(2gh) = v
sqrt(2(9.81)(1.5 - 1.5 cos 15))
v = 1.0 m/s
For number 2:
1/2 mv^2 = 1/2 ke^2
mv^2 = ke^2
e^2 = mv^2 / k
e^2 = (1.0 kg)(1 m/s)^2 / 750 N/m
e^2 = 1/750
e = sqrt(1/750)
e = 0.036 m
is this right?
Homework Statement
Hi, I have a question about pendelum which I don't know how to solve
A 1.0 kg ball swings from a pendulum and bounces into a spring with a spring constant of 750 N/m.
Here is the diagram:
1. How do i determine velocity of the ball at the bottom of the swing?
2. How do i...
Hi,
I have to do a lab simulation and fill out information in a chart. The lab simulates two pucks hitting with each other. It is suppose to be a momentum lab. I have filled most of the chart but am not sure if its correct. So I would like you to verify it. Plz and TY
These are the only...
for 2.(a) I did:
vf^2 = Vi^2 + 2ad
0 m/s = (21 m/s)^2 + s(-9.8 m/s^2)d
0 m/s = (441 m/s) - (19.6 m/s^2) d
0 - 441 m/s = -19.6 m/s^2 d
-441m/s / -19.6 m/s^2 = d
d = 22.5 m
since ur throwing the ball from a height of 1m: 22.5m + 1m =...