thank you... I knew I was missing something...
that is why I needed somebody to point that out...
I would have seen that if somebody had actually placed the #'s in an equation to get me there..so my math gets me 3936 / 5.95 = 661.5
convert from N-M to Ft-Lbs = 487.5 ft/lbs
that makes more...
so...
(20.05)/(3) = 6.683333
(1678)x(6.683333) = 11,2214.63277
(11.2214.63277)x(0.351) = 3936.336.104that isn't even remotely correct to measure force put out by an engine...
this is a vehicle that should be somewhere in the 400-600 ft/lbs torque Range
at 3000 rpm it should be 44.844 MPH
at 6000 rpm it should be 89.688 MPH
it too 3 seconds to accelerate a total of 44.844MPH
Tire Size is a Diameter of 27.61"
it is irrelevant what my actual individual rearend gear and transmisson gear is...the value I have provided is the total gear ratio...
I do know the MPH Associated with it...
or I can easily figure out the MPH the vehicle is traveling using RPM and Gear Ratios and tire size...
Hence why I gave the gear ratio in the first post..but I forgot to mention that tire size, which is 27.61" Diameter.again... I seem to be Math deficient...
sorry... that really doesn't mean much to me...
I'm looking for somebody who can walk me thru it...
gladly share any data needed to use formulas that anybody can supply to help me understand this so I can make a working software program.
I need some help coming up with a formula..
This involves a Vehicles Engine
I know how fast the rate of change is (example being 3000 rpm over 3 seconds-an increase from 3000rpm to 6000 rpm in that 3 second period)
I know how much weight this RPM has moved (3700 lbs)
and I know the Gear...
I have a wheel with a diameter of 26 inches that weighs 3900 lbs that is spinning at 100 MPH...
How much torque is needed to accelerate the wheel to 109 mph in 2.0 secondsanswer must be in ft-lbs
convert any units as necessaryplease show me the math so I can learn how to do this..I have a few...
so let me walk through this...
I will need some help...
I'll say my data says my tire is 26" Diameter...circumference of 40.84" or 3.403333 ft
My vehicle weight is 3900lbs which is what I'm calling my wheel weight
My data says
sample 1
0 seconds
100MPH
Sample 2
1 Second
109 MPH
so I have a...
ok...now I'm confused again
(Mass in LBS) * (Distance in radians?)^2 / (time in Seconds)^2
cause angular acceleration is in radians...
do I have to convert back to feet?
would it be easier to never convert to radians? just keep it in ft the whole way?
I guess where I'm having the issue is...
trying to calculate this all after all forces have been accounted for...
dont care about theoreticals...
all other forces = 0
all I want is math to do final result of what my vehicles actual force is...meaning I don't even care about gearing or anything...
um...thats why I am asking...
cause I don't know...
I'm actually looking for what formula I need to use...
I really don't know any of the formulas...
using google...
When I look up the Moment of Inertia I get
I = k? * Mass * Radius^2
but I have no Idea what K is supposed to be..
angular...
I'm trying to calculate Wheel torque in ft/lbs
things I know
Weight lbs or kg
Wheel Diameter inches or meters
acceleration data (I know how fast this wheel is spinning in MPH/kph/meters per second)and I know how much it changes over a given amount of time(meaning I know its going from "MPH1" to...
you lost me a little bit there...
so force = ft/sec^2 x Mass(which I can calculate that knowing the lbs...)
then that result x MPH
what is the 375 from?I need to know exactly where that # comes from...
I'm not worried about the deceleration just yet...
I need to know what the "BEST" formula for me to use is...
and I actually have 5 decimal places on all this data listed below..
the data I have is in samples taken in real time..
I need to come up with a way to calculate either the Torque or the Horsepower at the wheels...I can derive one from...