Recent content by SpaceTrekkie

I know that if you fire it at the equator, then it is deflected in its final landing position. But what would cause it to take longer to land? Gravity is still pulling it down at 9.8m/s^2... or am I totally missing something

Coriolis effect -- time to ground This is not a homework problem, I just have a conceptual question. Does the presence of the Coriolis effect, make a difference in how long it takes for a project tile to hit the ground. Obviously it makes a difference in its final location, but the time? Thanks!

I apologize, I was informed that that was a typo on the HW sheet, and it was actually asking for the radii and not the ratio.

Homework Statement The question is really long, so I am going to summarize the information that I have for the problem. I have two stars with their radial velocities Star1= 5.4 and Star2 = 22.4. The time period between first contact and minimum light is .58 days, the length of primary minimum...

okay I think I figured out the second one. It is a lot simpler than I was thinking. But 1, I still have no idea. My teacher's hint was use [PLAIN]www.physics.gmu.edu/~joe/PHYS428[/URL] topic 6 slide 15. But I do not see how that would work out...

ooo ok, I was missing the part about that it will equation to F=ma. Ahh I feel dumb now. Thanks for your help!

Homework Statement A particle of charge q and rest mass m0 moves in a circular orbit of radius R and angular frequency w in a uniform magnetic field b in the z direction: Find b in terms of R,q , m0, and w. Homework Equations b = (1/c) v X e and v = w/R and e = not sure. My problem is...

Homework Statement In frame S, two identical point charges q move abreast along lines parallel to the x-axis, a distance r apart and with speed v. Determine the force in S that each exerts on the other: a) using the lorentz force in conjunction with the field of a moving charged particle...

ooo ok. Thanks, I figured it out. The use of the boundary conditions are what was confusing me.

Homework Statement find the result <x> (the expectation value) found when the position of a particle in the second (n=3) excited state of a rigid box. Homework Equations <x> = (2/a)\intxsin2(xpi/a)dx evaluated from 0 to a The Attempt at a Solution well when that integral is...

sorry about the confusion of my notation. B = v/c, and yes, i did mean sin(theta in) = sin (theta_out). ooo ok, the so the Vm and Vl are not relevant to getting the answer, aside from the fact that they are clarifying the direction of the light. Was my approach of using the 4-momentum...

Okay, so in the rest frame the angle of reflection will be equal to the angle of incidence? So sin(theta_in) = -cos(theta_iin)? Which would give: P_in = (E/c)(sin(theta_in), -cos(theta_in), 0, 1) And thus P(prime)_in = (E/c) ( (gamma)sine(theta)in - B), -cos(theta_in), 0, (gamma)(1-B)) And...

Homework Statement A mirror moves perpendicular to its plane with speed (beta)c. A light ray is incident on the mirror from the \forward" direction (i.e., vm dot vl < 0, where vm is the mirror's 3-velocity and vl is the light ray's 3-velocity) with incident angle µ (measured with respect to...

Oh, okay, hmm...it was on our 4-vector HW for my relativity class and with no idea how to approach it I figured it was a 4-vector problem. Thanks for the tip, I will see if I can work it out from here.

Okay, I figured out that u-dot is the change in SPEED over time, while a = the change in VELOCITY over time. So the u-dot has no direction...but where to go from there, is still a mystery to me...