Recent content by SPYazdani

Don't let the space provided in a question throw you off. It has no value when solving problems. Don't get caught up in head games. If you rewrite the question as \int t^3 \cdot (3+t^3)^\frac{-1}{2} dt, it might be a bit easier. The only way I can see this problem being solved is...

The trick is to leave the negative sign in front of the incoming currents, rather than expanding it out like you have done in the first term in equation 1. That way, you won't make common mistakes when identifying the correct direction of the current. Also, if you move all your negative...

Heh, that's what our lecturer taught us :smile: :smile: Ok, I'm satisfied this problem is sufficiently solved. Thanks guys.

I didn't assume. The turns ratio is V1/V2 = N1/N2 = I2/I1 = 2400/240 = 10/1 Where did you get 24000 Volts from? Do you mean 24000 VA? They are two completely different quantities Where did you get 9.62 from? Nope.

Thanks rude man. I worked on this problem shortly after your last post and never got round to replying. I found I2 = 24000(0.8)/240 = 80 Amps --> arccos 0.866 = 30 degrees --> I2 = 80/_30 Amps Then E2 = V2 + I2Z2 = 240 + (80/_30)(0.04 + j0.12) = 237.97 + j9.91 Volts E1/E2 = a = 2400/240 = 10 So...

Ok for the purposes of the exercise, I'll try 24KVA and if I get stuck, I'll post back. Thanks

Homework Statement A step down transformer, 2400/240 V, 50Hz has the following resistance and leakage parameters. Z1 = R1 + jX1 = 4 + j12 Ω Z2 = R2 + jX2 = 0.04 + j0.12 Ω The transformer is operating at 80% of its rated load. The power factor of the load is 0.866 leading. Determine the...

For reliable communication, Lp is the minimum signal level required at the receiving antenna. It's a ratio of \frac{P_T (mW)}{P_R(mW)}. The distance R = \frac{\lambda\sqrt{L_P}}{4\pi}. Rearranging and solving for L_P = (\frac{4R\pi}{\lambda})^2 implies the loss is related to the distance...

Homework Statement Plot and compare the path loss (dB) for the free-space and plane-Earth models at 800MHz vs distance on a logarithmic scale for distances from 1m to 40Km. Assume that the antennas are isotropic and have a height of 10m Homework Equations Free space: P_R=\frac{P_T G_T...

:smile:

What do you think?

\theta_{difference}=\theta_{1}-\theta_{2}

Probably to prove that OP understands the concept in an upcoming exam because giving a decimal answer is proof enough of using a prohibited calculator

Thank you very much for your help. My lab report is now complete and ready for submission :D Also, a side question, in the lab report, he asked us to provide two phasor diagrams. One for 1000Hz and another for 3000Hz. They both appear to be roughly 1KHz above and below the resonance frequency...

Me either. That's weird. Try the attachment