Isotropic antenna Transmit and Receive power

AI Thread Summary
The discussion focuses on calculating and comparing path loss for isotropic antennas using free-space and plane-Earth models at 800MHz over distances from 1m to 40km. The equations for received power (P_R) are simplified due to the isotropic nature of the antennas, leading to the relationship P_R = P_T / L_P, where L_P is the path loss. The user struggles with determining the transmitted power (P_T) and understanding the significance of L_P, which represents the minimum signal level required for reliable communication. Clarification is provided that L_P is related to both the distance between antennas and the wavelength of the transmitted signal. The discussion concludes with the user expressing gratitude for the assistance received in solving their problem.
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Homework Statement


Plot and compare the path loss (dB) for the free-space and plane-Earth models at 800MHz vs distance on a logarithmic scale for distances from 1m to 40Km. Assume that the antennas are isotropic and have a height of 10m


Homework Equations



Free space: P_R=\frac{P_T G_T G_R}{L_P}

Plane Earth: P_R=P_TG_TG_R(\frac{h_Th_R}{R^2})^2

Two isotropic antennas separated by a distance R\epsilon[1m,40km] at frequency f=800MHz.




The Attempt at a Solution


Isotropic antennae have G_T=G_R=1. So That simplifies P_R=\frac{P_T G_T G_R}{L_P} = P_R=\frac{P_T}{L_P}
L_P=(\frac{R4\pi}{\lambda})^2.

I'm solving the question for 1m for the free space model, then once I have that, plotting it is easy in Excel.

I'm stuck on finding P_T. I tried deriving an equation for P_Tby substituting L_P=(\frac{R4\pi}{\lambda})^2 into P_R=\frac{P_T}{L_P} but that lead me nowhere. At least I don't know what the answer means.

Here's what happened.

P_R=\frac{P_T}{R^24\pi}A_e
P_R=\frac{P_T}{L_P}
L_P=(\frac{R4\pi}{\lambda})^2
\frac{P_T}{R^24\pi}A_e=\frac{P_T}{(\frac{R4\pi}{λ})^2}
Then a bunch of cancellation on both sides and finally
Ae 4\pi = \lambda^2

Help! I don't know how to find P_T
 
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What is Lp? How does it relate to what you are asked for?
 
marcusl said:
What is Lp? How does it relate to what you are asked for?

For reliable communication, Lp is the minimum signal level required at the receiving antenna. It's a ratio of \frac{P_T (mW)}{P_R(mW)}. The distance R = \frac{\lambda\sqrt{L_P}}{4\pi}. Rearranging and solving for L_P = (\frac{4R\pi}{\lambda})^2 implies the loss is related to the distance separated by the antennas as well as the wavelength of the transmitted signal.

Thanks for pointing that out. I can now solve my problem :D
 
You're welcome!
 
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