Recent content by struggtofunc

Oh I see, so an octave would be twice the frequency? I'm simply just doubling 283Hz to 566Hz

Homework Statement The fundamental frequency of a violin string is 283 Hz. Calculate the frequency of the 2nd harmonic. Known: f = 283 Hz Homework Equations v = fλ f(n) = n*v/2L λ= L v(sound) = 343 m/s The Attempt at a Solution λ = 343/283 = 1.21 m f(2) = 2*343/2*1.21 = 283 Hz. I'm getting...

No worries. Thank you very much for your help!

Hi chestermiller, Yes, I input the answer as 230 J/kg/K because it was what we were told to present it in. It's still showing as incorrect though.

c = 247950/(4.96*217.3) = 230. 05 J/kg/K

Homework Statement A 4.96 kg piece of solid material is heated from 16.7oC to 234oC (3 s.f.) using 725 kJ of energy (3 s.f.). Assuming an efficiency of 0.342 for the heating process, and that the material does not melt, calculate the specific heat capacity of the material. m = 4.96 kg change...

Thank you so much! I really appreciate the help :)

Oh yes, I see. Thankyou very much! Using that then: P1-P2= ½ * ρ ( v2^2 - V1^2) change in pressure = 1/2 (1.29)(3.89^2) = 9.7602045 Pa. Am I now right to believe that I can use this value in P=F/A to calculate force? It is a change in pressure so I'm unsure what...

I'm really sorry but I think I am confusing myself now. I've rearranged P1 + (½ * ρ * v1^2) = P2 + (½ * ρ * v2^2) to become P1-P2= ½ * ρ ( v2^2 - V1^2). This would allow me to get a change in pressure. However, Velocity is not changing so i would be getting a 0 value for v2^2 - V1^2 and...

So using Bernoulli's equation: P1 + (½ * ρ * v1^2) + (½ * ρ * g * h1) = P2 + (½ * ρ * v2^2) + (½ * ρ * g * h2) Because the wind is flowing parallel, it would be considered horizontal allowing me to cancel out the heights giving me the equation of P1 + (½ * ρ * v1^2) = P2 + (½ * ρ * v2^2)...

Homework Statement The doorway in the previous question measures 1.06 m x 2.04 m, and the wind blows parallel to the wall surface at 3.89 m.s-1. Calculate the force pushing the curtains out of the doorway. The density of air is 1.29 kg.m-3. Known data: A = (1.06m)(2.04m) = 2.162 m^2 v(wind)...

Thanks for all the help everyone! I've calculated the time using two equations rather than quadratics: v^2 = v(i)^2 + 2a(x-x(i)) v^2 = (4.00)^2 + 2(-9.8)(-1.80) v = square root of 51.28 = +- 7.16 ms-1 v = v(i) + at t = (+-7.16 - 4.00)/(-9.8) t = - 0.32 s t = 1.14 s Thank you all so much! J

Thankyou for your help! Would it be appropriate to solve this in two steps? One to reach the peak of trajectory motion and one to reach the pool?

Thanks for your reply! I think I see the problem now. So because the question is asking for time in the air, my V(f) value should be calculated just before she reaches rest. Thankyou!

Hello everyone! Apologies if this is a very repetitive question but I have gone through previous forum posts and am still struggling to understand how to identify which equations are appropriate. In the problem below, I have used the kinematic equation of "v = v(i) + at" but my answer is...