Calculating Specific Heat Capacity

AI Thread Summary
To calculate the specific heat capacity of a 4.96 kg solid material heated from 16.7°C to 234°C using 725 kJ of energy with an efficiency of 0.342, the effective energy used is 247950 J. The formula used is c = Q/(m*change in T), resulting in c = 230.05 J/kg/K. However, the answer is reported as 230 J/kg/K, which may not be accepted due to significant figures or unit preferences. Despite confirming the calculations, the result is still marked incorrect, indicating a potential issue with how the answer is presented or interpreted. Further clarification on reporting standards may be needed.
struggtofunc
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Homework Statement


A 4.96 kg piece of solid material is heated from 16.7oC to 234oC (3 s.f.) using 725 kJ of energy (3 s.f.).

Assuming an efficiency of 0.342 for the heating process, and that the material does not melt, calculate the specific heat capacity of the material.

m = 4.96 kg
change in T = 217.3 celsius
energy = 725000 J
efficiency = 0.342

Homework Equations


Q = (m)(c)(change in T)

The Attempt at a Solution


c = Q/(m*change in T)

I have calculated Q using .342*725000 = 247950.

I then plugged in these values into the equation and am still getting the wrong answer.

I've also tried dividing 725000/.342 and plugging those values in but it's still incorrect.

What should I be doing in regards to the efficiency?

Thanks!
 
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struggtofunc said:

Homework Statement


A 4.96 kg piece of solid material is heated from 16.7oC to 234oC (3 s.f.) using 725 kJ of energy (3 s.f.).

Assuming an efficiency of 0.342 for the heating process, and that the material does not melt, calculate the specific heat capacity of the material.

m = 4.96 kg
change in T = 217.3 celsius
energy = 725000 J
efficiency = 0.342

Homework Equations


Q = (m)(c)(change in T)

The Attempt at a Solution


c = Q/(m*change in T)

I have calculated Q using .342*725000 = 247950.

I then plugged in these values into the equation and am still getting the wrong answer.

I've also tried dividing 725000/.342 and plugging those values in but it's still incorrect.

What should I be doing in regards to the efficiency?

Thanks!
Please show the details of your calculation of c.
 
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c = 247950/(4.96*217.3) = 230. 05 J/kg/K
 
struggtofunc said:
c = 247950/(4.96*217.3) = 230. 05 J/kg/K
This looks OK, but isn't it usually reported as kJ/kg/K? Also, shouldn't the significant figures be less?
 
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Hi chestermiller,

Yes, I input the answer as 230 J/kg/K because it was what we were told to present it in. It's still showing as incorrect though.
 
struggtofunc said:
Hi chestermiller,

Yes, I input the answer as 230 J/kg/K because it was what we were told to present it in. It's still showing as incorrect though.
I don't know what else to suggest. This answer looks correct.
 
No worries. Thank you very much for your help!
 
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