Recent content by tarletontexan

yes, I know that there are several maxwell relations to get to the solution I just don't know how to apply them.

what does health physics entail? I am interested in either nuclear engineering or Health physics but would like to get more detail on what it is that they actually do? Anybody know and want to help out?

Homework Statement cp=cv+TV?^2/? Homework Equations cp=T/N(\partialS/\partialT)p The Attempt at a Solution I have the equation, just not sure how to apply it? Any help would be appreciated

ok so if the particle is supposed to be in between 0 and L/4 then I'm going to get 4/L because it is 1/4 of the total length of the box...

so how/where would i begin normalizing that??

Homework Statement A particle of mass m is located in a box of length L and found to be in its ground state A) what is the probability of finding the particle between x=0 and x=L/4 B) What is the expectation value for the position of the particle? C)What is the expectation value <x^2>...

ok, i see, but the example in the book has the initial wavefunction given as Y(x,0)=Cexp(-|x|/x0) where C and x0 are constants, is it possible to get this function into a similar format??

that is not given, the only thing it asks for in this part of the problem is what value of C is required to normalize Y(x,0)...

its the operator...

Homework Statement Consider a particle in a superposition of states given at time t=0 by Y(x,0)=C(y1(x)+y2(x)), where y1(x) and y2(x) are the stationary states with energies E1 and E2 respectively. if y1(x) and y2(x) are orthonormalized, what value of C is required to normalize Y(x,0)...

\psi is psi, and i mean [x] times \psi would be [x]Acos(kx).

wait, so x is the operator and if it multiplies times Acos(kx) or Acos(kx)+iAsin(kx) then wouldn't it be the same as multiplying x(psi)?

ok thanks, i think I have bridged the gap in my knowledge, one more quick question though...in Acos(kx)+iAsin(kx) the i doesn't play a role does it? I mean its just like a negative sign??

ok, that makes some sense, so since the position operator [x] is just x, then all of the functions are eigenfunctions...similarly, the potential energy operator [U] is just the potential energy function. In this case the function is zero so since its [U]=0 all the functions are eigen functions...

Homework Statement given the following functions: y(x)= Acos(kx) y(x)=A sin(kx)-Acos(kx) y(x)=Acos(kx)+iAsin(kx) y(x)=A d(x-x0) Which are eigenfunctions of the position, momentum, potential energy,kinetic energy, hamiltonian, and total energy operators Homework Equations y(x) is...