Recent content by TickleMeElma

Ok, that makes perfect sense. But what do you mean when you say omega?? thanks.

In a "rotor-ride" at a carnival, people are rotated in a cylindrically walled "room." The room radius is 4.6 m, and the rotation frequency is .5 revolutions per second when the floor drops out. What is the minimum coefficient of static friction so that the people will not slip down? I am...

Thank you so much for your help - yeah, somehow, I missed the sample problem that dealt with the apparently widely-known concept of 45 degrees being the angle that yields the max horizontal replacement. Went back and reworked it with your suggestions and those of the book and got ~39m. :)

You buy a plastic dart gun, and you wnt to find its max. horizontal range. you shoot the gun straight up, and it takes 4s for the dart to land back at the barrel. What is the maximum horizontal range of your gun? I got the initial velocity, which is 19.6 m/s. I know I have to incorporate...

Ok, what if we don't even use time, except to find the velocity? Having that information, we can find the position, assuming that the acceleration is -9.8m/s^2?

I appreciate your advice, but I am still confused. I am using the equation for motion, yes. But it asks for time, and the time from the moment of fall is not the same as the time it took the rock to fall along the window, which means that t is the variable that cannot be used, but is needed...

A falling stone takes 0.28s to travel past a window 2.2m tall. From what height above the top of the window did the stone fall? So we have time and dinstance, but not the acceleration, which confuses me terribly. Do I need to find velocity? Or do I need to look for the acceleration? SO...

Thanks so much!

A motion picture is made of a stone falling down. It shows that the acceleration is downward. Now run the film backwards. It will show the stone accelerating upwards. True or false? I am not sure on this one...I think it is false, because if traced backwards, the stone is actually...

Hey all smartie-pants! So this is the problem I have a tough time with: The magnetic field perpendicular to a single 13.2-cm-diameter circular loop of copper wire decreases uniformly from 0.750T to zero. If the wire is 2.25mm in diameter, how much charge moves past a point in the coil...

Thanks so much for your input. I solved it, you were right. :)

A 3.4g bullet moves with a speed of 160 m/s perpendicular to the Earth's magnetic field of 5x10^-5T. If the bullet possesses a net charge of 13.5 x 10^-9 C, by what distance will it be deflected from its path due to the Earth's magnetic field after it has traveled 1 km? I am confused. Do I...

Thanks, that's what I did. I multiplied the total charge of a proton by the number of those crossing that point per second.

Ok, so I am not sure if this is right, but 1.5x10^9 is also the current, I. So the other variables that are given are r and the permeability of free space constant, 4(pie)x10^-7. So I plugged all that into the equation for B, the magnetic field, which is (perm. constant)xI/2(pie)r thanks :)

I have tried everything to solve this problem, and I just cannot come to a conclusion. If anyone finds it comes easy to them, help will be greatly appreciated. :) Here goes: A straight stream of protons passes a given point in space at a rate of 1.5x10^9 protons/s. What magnetic field do...