Constant acceleration of velocity

[TickleMeElma]

A falling stone takes 0.28s to travel past a window 2.2m tall. From what height above the top of the window did the stone fall?

So we have time and dinstance, but not the acceleration, which confuses me terribly. Do I need to find velocity? Or do I need to look for the acceleration? SO confused. Any help will be greatly appreciated.

Thanks!

 

[hotvette]

It always helps to draw a picture and free body diagram, then write the equation of motion, and solve for what you want. In this case, you have a rock of mass m, acted upon by gravity g, falling from rest, starting from a height x above the window. What you are given is the time it takes to cover a certain distance during it's fall to the ground. Hope this helps get you thinking in the right direction.

 

[TickleMeElma]

I appreciate your advice, but I am still confused. I am using the equation for motion, yes. But it asks for time, and the time from the moment of fall is not the same as the time it took the rock to fall along the window, which means that t is the variable that cannot be used, but is needed for the equation to find the distance covered. And, yes, drawing a diagram is the first thing I do... :)

 

[hotvette]

Let me try this way. You have an equation of motion that relates distance fallen (from an unknown point above the window) as a function of time. Seems to me a fruitful approach is to express that equation of motion for x_1, t_1 and x_2, t_2, where x_1 represents the top of the window and x_2 represents the bottom of the window. Subtracting the 2 equations gives you x_1 - x_2, which you know.

 

[TickleMeElma]

Ok, what if we don't even use time, except to find the velocity? Having that information, we can find the position, assuming that the acceleration is -9.8m/s^2?

 

[hotvette]

Had to do a little head scratching. I believe the following will work:

Using the equation of motion of the rock you should be able to get an equation for x_1-x_2 in terms of g, t_1^2 and t_2^2. You know x_1-x_2, and g, but not t_1 or t_2. But, you do know t1-t2. Thus, you have two equations in two unkowns and should be able to solve for t_1, back substitute into the equation of motion, and find x_1.

 

[hotvette]

Were you able to solve it? I got x_1 equal to a little over 2m using the above methodology.