Recent content by toboldlygo

Oh, that makes sense! So if I were to subtract initial from final, I'd get x-(-x), which is just 2x, right? Or did I completely miss the mark?

It couldn't, if its velocity were zero. Does that mean it hits the pan with twice the velocity? There can't be zero change in velocity, could there? I know what you're saying now, but I don't know how I would factor that into a solution.

After it hits the pan, the beads bounce back up to their original height. But how does that factor into the velocity? The velocity of the bead is 3.1006 m/s before it hits the pan, and then zero when it does. Isn't that a change of 3.1006 m/s?

Here's my work. I've attached it to the reply.

Homework Statement [/B] A stream of elastic glass beads, each with a mass of 0.53 g, comes out of a horizontal tube at a rate of 99 per second. The beads fall a distance of 0.49 m to a balance pan and bounce back to their original height. How much mass must be placed in the other pan of the...

Oh wow, that simplifies things so much. Thank you! Even though I've been using vectors for well over five weeks now I completely forgot.

Homework Statement [/B] A shell of mass m and speed v explodes into two identical fragments. If the shell was moving horizontally (the positive x direction) with respect to Earth, and one of the fragments is subsequently moving vertically with speed v, find the velocity v of the other fragment...

They're asking for the uncertainty of the predicted velocity, and using σ to depict that. Doesn't σ and uncertainty denote the standard deviation?

Homework Statement A screen grab of a DataStudio run with a cart being pulled by a rubber band connected to a force sensor attached to the end of the track is shown below. The two graphs have the same horizontal axis: position of the cart from the motion sensor. The vertical axis on one graph...

@Ray Vickson, @ehild: I actually did the whole problem instead of just one part and got the right answer. Who'dathunk? I guess I got caught up in just the first part. This is what happens when the right answer is directly underneath the problem haha. Thanks for helping me out! :smile:

No; it'd just depend on on the applied force, right? So the rule of thumb for normal force is just, "Well, it depends." I guess I'm not going to be able to get out of drawing a free body diagram haha

So normal force is mathematically dependent on gravity, theta, and an applied force, assuming there are no other forces acting on an object. Correct? And are there any situations in which I apply a downward force to an object and the normal force doesn't increase?

I'm thinking the Normal force has to increase to balance out the applied force, but I think I'm mostly confused about what exactly the Normal force is. I know that it's mgsin/cos(θ) (depending on which way the object is oriented and all that), but I also know that it's a reaction force from the...

So, I know that there is a Normal force exerted on the book by the table, and, according to Newton's Third Law, the book exerts a force onto the table. However, I have two questions: if I were to push down on the book, would that Normal force increase? What "creates" the Normal force? Is it the...

Wow. I completely misread that haha. Sorry about that. So, I probably simplified (x^2+y^2+z^2)^{1/2}(4x^2+y^2+z^2) incorrectly, but I think that's the correct derivative. If so, is there a way to manipulate the expression so I get 2r?