Recent content by tome101

290 views and no-one has any thoughts on this? I'm still completely stumped! I've also just noticed i should say u(H)=U under the attempted solution

Homework Statement Water flows down a channel whose floor is porous, so that water seeps out of the bottom of the channel at a speed v, where v is constant and much less than the flow speed, U, along the surface of the channel. The seepage rate is slow so that H may be regarded as constant...

Homework Statement A) A tank of water of cross-sectional area A empties through a pipe of cross-sectional area a, where a A so that the speed of the water flow in the tank can be neglected compared to that in the pipe. The initial height of the water in the tank is H and the pipe extends a...

Ok, I've now been told that the surface integral of E*dA in this case goes to E(4pi*r^2) but I'm still not totally sure why.

OK, by integration I've found the charge enclosed by the sphere to be (4pi*k*r^5)/5, but I'm not really sure where to go from here? From \oint _S \vec{E} \cdot \vec{dA} = \frac{Q_{enclosed}}{\epsilon_0} I can see that I need to divide the charge enclosed by epsilon 0 then equate to the...

Homework Statement Compute the electric field generated by a spherically symmetric charged sphere of radius R with charge density of \rho = kr^{2} Homework Equations \oint _S \vec{E} \cdot \vec{dA} = \frac{Q_{enclosed}}{\epsilon_0} The Attempt at a Solution I know that this question...