Calculating Electric Field of Spherical Charge Distribution

AI Thread Summary
To compute the electric field of a spherically symmetric charged sphere with a charge density of ρ = kr², Gauss' law is applied. The user attempts to find the enclosed charge using integration, resulting in Q_enclosed = (4πkr⁵)/5. They express confusion about calculating the surface integral of E*dA, which is simplified to E(4πr²) due to symmetry, as the electric field is constant over the Gaussian surface. The discussion emphasizes the need for clarity in applying Gauss' law and understanding the relationship between the electric field and charge distribution. Overall, the thread highlights the challenges of applying theoretical concepts to practical problems in electrostatics.
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Homework Statement


Compute the electric field generated by a spherically symmetric charged sphere of radius R with charge density of \rho = kr^{2}


Homework Equations


\oint _S \vec{E} \cdot \vec{dA} = \frac{Q_{enclosed}}{\epsilon_0}

The Attempt at a Solution


I know that this question involves the application of Gauss' law but I don't really know how? To be honest I'm a bit sketchy on applying Gauss' law to any question. Any help would really be appreciated.
 
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Imagine a Gaussian sphere of radius r, centered on the actual sphere of charge. What would the surface integral of E*dA be, in terms of r? Remember that due to symmetry, the electric field has to be constant for constant r, and must be entirely radial.

Using integration, can you also find Q_enclosed for this Gaussian sphere?
 


OK, by integration I've found the charge enclosed by the sphere to be (4pi*k*r^5)/5, but I'm not really sure where to go from here?

From
\oint _S \vec{E} \cdot \vec{dA} = \frac{Q_{enclosed}}{\epsilon_0}
I can see that I need to divide the charge enclosed by epsilon 0 then equate to the surface integral of E*da, but I'm not really sure how to calculate the surface integral of E*da?
Thanks
 


Ok, I've now been told that the surface integral of E*dA in this case goes to E(4pi*r^2) but I'm still not totally sure why.
 
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