Calculating Electric Field of Spherical Charge Distribution

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SUMMARY

The discussion focuses on calculating the electric field generated by a spherically symmetric charged sphere with a charge density of ρ = kr². The application of Gauss' law is essential, specifically using the equation ∮_S E · dA = Q_enclosed/ε₀. The charge enclosed within a Gaussian sphere of radius r is determined to be (4πkr⁵)/5. The surface integral of E · dA simplifies to E(4πr²), which is derived from the symmetry of the electric field being constant at a given radius.

PREREQUISITES
  • Understanding of Gauss' law in electrostatics
  • Familiarity with spherical symmetry in electric fields
  • Knowledge of charge density concepts
  • Basic integration techniques for calculating enclosed charge
NEXT STEPS
  • Study the derivation and application of Gauss' law in electrostatics
  • Learn about electric field calculations for different charge distributions
  • Explore the concept of electric flux and its relation to surface integrals
  • Investigate the implications of symmetry in electric field calculations
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Students in physics, particularly those studying electromagnetism, as well as educators and anyone seeking to understand electric fields generated by spherical charge distributions.

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Homework Statement


Compute the electric field generated by a spherically symmetric charged sphere of radius R with charge density of \rho = kr^{2}


Homework Equations


\oint _S \vec{E} \cdot \vec{dA} = \frac{Q_{enclosed}}{\epsilon_0}

The Attempt at a Solution


I know that this question involves the application of Gauss' law but I don't really know how? To be honest I'm a bit sketchy on applying Gauss' law to any question. Any help would really be appreciated.
 
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Imagine a Gaussian sphere of radius r, centered on the actual sphere of charge. What would the surface integral of E*dA be, in terms of r? Remember that due to symmetry, the electric field has to be constant for constant r, and must be entirely radial.

Using integration, can you also find Q_enclosed for this Gaussian sphere?
 


OK, by integration I've found the charge enclosed by the sphere to be (4pi*k*r^5)/5, but I'm not really sure where to go from here?

From
\oint _S \vec{E} \cdot \vec{dA} = \frac{Q_{enclosed}}{\epsilon_0}
I can see that I need to divide the charge enclosed by epsilon 0 then equate to the surface integral of E*da, but I'm not really sure how to calculate the surface integral of E*da?
Thanks
 


Ok, I've now been told that the surface integral of E*dA in this case goes to E(4pi*r^2) but I'm still not totally sure why.
 

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