Recent content by tommy2st

Find Devivaties with respect to x: 1). y=sin(cos(x+3)); 2). tan(x+y)=ln x+ 5y. heres my work...just need a double check 1). y=sin(cos(x+3)); 2). tan(x+y)=ln x+ 5y. 1:y = sin(cos(x+3)) y' = cos(cos(x+3))(-sin(x+3))(1) y' = {-sin(x+3)}{cos(cos(x+3))} 2. Tan(x+y) = lnx+5y...

i figured it out. the answer was -7+ (9+e^2)^1/2

it can be broken down further into something more simplified. the example i have goes down from x^2 + 4x -(e^2 + 5)=0 to x= -2+-sqrt 9+e^2 but it doesn't show the steps used

natural log helpp! Homework Statement ln(x+10)+ln(x+4)=2 2. The attempt at a solution okay so i took it down to (-14+-(14^2 - 4(e^2 - 40))^1/2) / 2 which i broke down to 356 - 4e^2 inside the sqrt. am i on the right track and if so Whats the next step?

i figured it out now. i was squaring the base instead of cubing it. thanks for your help tho !

anybody?

Homework Statement [SIZE="4"]log[SIZE="1"]6[SIZE="4"](x+6) - log[SIZE="1"]6[SIZE="4"](x-4) = 3 2. The attempt at a solution 150/36 is what i get which i simplified to 25/6. but the program tells me I am wrong can anyone think of how I am getting this wrong

thank you so much for your help doc!

okay thank you ill try and edit this t=1.5 d=(15)(1.5)+(1/2)(-10)(1.5^2)= 11.25? or (30)(1.5)+(1/2)(-10)(1.5^2)= 33.75? i think its the second one

average speed 15 m/s? also i need help with this part... On the way up, at what height is the speed of the ball equal to half its speed of projection? i get that it wants me to find at what distance v = 15 but I am having trouble munipulating the equations to solve this

would it be d= 30*3 + 1/2(-10)(3^2)? giving me 45?

anyone?

0 is the final velocity. is the answer 3s? i think i may have got it 30=10t t=3 anyone am i right? also the height it reaches using 3? would i use d=30*3 + 1/2(10)(3^2)

Homework Statement A ball is thrown vertically upward from the ground with an initial velocity of 30 m/s. Assume the acceleration due to gravity is g = 10 m s-2. How long will it take for the ball to rise to the highest point on its trajectory? (AF:no decimals) i got v1 = 30m/s a=...

Homework Statement Points: 3) A vector X is added to vector Y = 12i -16j. The resultant vector lies along the positive x-axis and has the same magnitude as X. What is the magnitude of X? a. 20.7 b. 16.7 c. 11.3 d. 4.7