Recent content by transparent

Hello. I know there are quite a few threads about this, but I couldn't find what I was looking for. This topic has been driving me crazy over the last couple of days. I know the cause behind the precession. It's because the torque due to gravity about the pivot tends to rotate the already...

Thanks. What about the charge? Will there be any charge on the inner surface of the shell? Also, how does the shielding effect work?

If a spherical conducting shell is kept in an electric field (say, from a point charge kept at some distance outside the shell), will any charge be induced in the internal surface of the shell? Also what will the field be like inside the shell? Thanks.

How do I tell if a torque on a system is internal or external before conserving angular momentum? I know that if a force has its reactionary force in the system, then it is an internal force and we can conserve the linear momentum of the system. But I don't know how to recognize a reactionary...

Thanks.

I suppose you're right. Three forces acting on a point will give zero iff the angles between them are 120 degrees. Thanks. The answer is in fact √7 R. Could you show me how you got that?

That earlier question was: Two bubbles of radius R1 and R2 (R1>R2) come in contact with each other and deform. What is the Radius of curvature of the common surface? The answer was (R1R2)/(R1-R2) We do ignore the change in volume. There was another question which said: Two bubbles, each...

The bubbles do deform. The question is in the Surface Tension section in my textbook. I got 3R/2 by calculating pressure difference across the common surface and equating it with 4T/R'. There was a question before this one where we had to do this.

Homework Statement Two bubbles, one of radius R and the other of radius 3R come into contact with each other. What is the distance between the centres of the two bubbles? Ignore the weight of the bubbles. Homework Equations p(inside bubble)= p(atm) + 4T/R where T is the surface tension and R...

Why? And isn't the centre of mass accelerated? Edit: Didn't read "other than the centre of mass" part. But still, why is it so?

Tell me where I've gone wrong (here r(1,2) means position of point 1 with respect to point 2 etc): ω x r(1,2)=v(1,2) Differentiating both sides with respect to time: ω x v(1,2) + \alpha x r(1,2) = a(1,2) =>ω x (ω x r(1,2)) + \alpha x r(1,2) = a(1,2) Now let us imagine a uniform rod in free...

That makes sense. But ∫v.dp should mean something since dH=dU+pdV+Vdp. Here dU is the change in internal energy and pdV is the work done. What is Vdp?

What is the difference between ∫X.dY and ∫Y.dX in the physical world? I know what the difference is in pure mathematics. ∫X.dY represents the are bounded by the curve and the Y axis while ∫Y.dX represents the area bounded by the curve and the X axis. But I am unable to translate this into...

I suppose you are right. I always imagined that the basic axioms of the universe would be much simpler than this.:frown: Gauss's law is simply based on the fact that if any curve enters/exits a closed Gaussian surface, it must exit/enter it as well, as long as it does not have an end/origin...

So is it an axiom? I always thought they declared a law only after some mathematical proof. I mean, for all we know, the experiment might be erroneous. Edit:Were all Maxwell's equations experimentally determined? Gauss's law seems pretty intuitive. I can't understand the others.