I was doing some practice problems to become more familiar with the Center of Mass Velocity and I came across this one from (Noted in the picture) Engineering at Illinois, that relates the velocity of the center of mass in both the x and y direction, however I don't quit understand the answer...
Here's a question that I've been trying to solve for a while but keep on running into dead ends, and I can't seem to find any info on the internet to help me. Anyways I was wondering what the integral of torque is? For my specific example I have a rod that is not equally balanced on a fulcrum...
So I've learned that the torque on an object is just: (perpendicular force)(radius) and that has worked well for things like seesaws but it doesn't take into account the torque of the object itself!
In the picture the rod has a total mass of 5kg, and by definition the torque on the right is...
So you are saying that adding up their accelerations would be the true acceleration of gravity? By that logic, does that mean that an object of higher mass would indeed fall faster than a lower mass object due to the fact that the higher mass object pulls the Earth towards it more, thus...
I know that the force of gravity is (ma)=GMm/r^2 or a=GM/r^2
This makes sense and If I were to drop a bowling ball down to Earth I'd expect it to fall with 9.8m/s^2. However I can calculate that the bowling ball has its own gravity using the formula noted above. My question is what will be the...
Yea I'm familiar with them, and my problem was that I could calculate the amount of energy that went towards rotational kinetic energy. PE=1/2mv^2 + 1/2Lw^2 , and this makes sense when compared to a cube that isn't rotating so would have PE=1/2mv^2 . So my question is how slower would the ball...
So I know that given a unchanging hill, and same mass between a sphere and cube, that the cube should slide down the hill faster (assuming negligible friction). This is observed through the energy "lost" by the sphere which instead of having all of its potential energy transferred towards...
So recently I've become familiar with concepts like specific heat, and we use a formula Q=mcΔT to calculate the Joules necessary to heat up say a kg of water from 50 to 70 degrees celsius. Now I was wondering if there is a equation that incorporates the amount of heat lost to the atmosphere...