Recent content by tyco05

This is a very important point that regularly catches people out. If the slope is constant, then you know that the acceleration is constant, so you can use the SUVAT equations. jgens pointed out the relevant one to use - and don't forget to add the extra displacement due to the initial...

My bad.

My take on it is this: If you double frequency, you DOUBLE the number of photons passing a given point per second. According to E=hf, you ALSO DOUBLE the energy of each individual photon. 2x energy per photon, and 2x amount of photons gives 4x total energy.

If I'm not mistaken, your graph shows the x-component of the velocity against time - so you should be able to simply read from the values from the graph. You also must be careful as the units on the graph are cm/s - and the question is asking for m/s. As for the acceleration, it looks as...

Read the rules.

I think you are making it harder for yourself than it actually is. Just use simple velocity addition.

I don't know what level you are at lha, but I'm thinking all of the equations above might be confusing you. In my opinion, a simpler model for a SHM oscillator is a simple pendulum. Imagine it was swinging in the plane of the page. And take right as the positive direction. At the left...

I've only briefly thought about your attempt: You are only considering the upward forces due to the spring. What about the force on each object due to gravity... will it be the same? Consider...

From what I can tell your equivalent resistances are ok. If the supply is 12V - YOUR calculation for current gives you the current through R1. This splits at the next junction - in inverse proportion to the resistances of R2 and R3.

Gold has an atomic number of 79 - hence 79 protons in the nucleus. The charge is then 79e. What do you think this would be for Lead? You might need a periodic table to help you with this one.

What sort of cable? What is happening with the cable? How does a compass work? Why might whatever is happening affect a compass?

Maybe, maybe not. Depends.

I can't open your link.

Your current calculations look ok. You have used the wrong value for voltage. Remember that only a proportion of the 25V is used in the 5 ohm resistor. I'll leave it up to you to figure out what the value should be. Oh, and you've substituded wrongly also...

The initial vertical component of the velocity is given by Uy = Vo*sin(theta). You don't need any of that other business. You can use Vy = Uy + Ay*t with the given time to find the vertical component of the velocity. Remember to define a positive and negative. It will probably be...