What is the Q value for lead in the Rutherford Experiment?

Click For Summary
SUMMARY

The Rutherford Experiment involves calculating the Q value, which represents the charge of a nucleus. In this discussion, the Q value for gold is established as 79e due to its atomic number of 79. For lead, which has an atomic number of 82, the Q value is definitively 82e. This indicates that lead has 82 protons in its nucleus, resulting in a higher charge compared to gold.

PREREQUISITES
  • Understanding of atomic structure and atomic numbers
  • Familiarity with the Rutherford scattering experiment
  • Basic knowledge of nuclear charge and Q values
  • Ability to read and interpret a periodic table
NEXT STEPS
  • Research the implications of different Q values in scattering experiments
  • Learn about the Rutherford scattering formula and its applications
  • Explore the properties of lead and its uses in scientific experiments
  • Investigate the historical significance of the Rutherford Experiment in nuclear physics
USEFUL FOR

Students of physics, educators teaching atomic theory, and researchers involved in nuclear physics experiments will benefit from this discussion.

the whizz
Messages
32
Reaction score
0
in a problem using the Rutherford scattering experiment, i Need to find what the turning distance would be using lead instead of gold. I have that gold has a Q= 79e, what would the Q = ?? for lead?
 
Physics news on Phys.org
Gold has an atomic number of 79 - hence 79 protons in the nucleus. The charge is then 79e.

What do you think this would be for Lead? You might need a periodic table to help you with this one.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K