Recent content by typeinnocent

I'm sorry, but I'm really confused by your explanation. You said that for f(x)*, "complex conjugation is being applied to the value of f(x)." Do you mean then, that the complex conjugation is being applied to the roots of f(x), since those give the values of f(x)? Perhaps I'm reading my...

Homework Statement Consider: y = f(x) = ax^2+bx+c, where a, b and c are real constants. Prove that y*=f(x*) Homework Equations conjugate of a complex number x=a+jb and x*=a-jb The Attempt at a Solution You can show the answer of f(x*) by substituting (a-jb) for each x in f(x), but...

Homework Statement If the maximum kinetic energy given to the electrons in a Compton scattering experiment is 10 keV, what is the wavelength of the incident X-Rays? Homework Equations \Delta\lambda = (h/mc)*(1-cos\theta) E = hc/\lambda \Delta\lambda = \lambdascattered - \lambdaincident...

Homework Statement Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density n = 990 wires/m and a current per wire of IL = 0.19 A in the +z direction...

Oh, wow. See, I had thought my entire methodology was incorrect... I didn't realize I was actually close to the answer for part a). Thanks! Now I at least have part a) correct.

I don't want to be rude, but that really doesn't help me... I still don't know what to do.

There's two protons per alpha particle.

Homework Statement Assume a steady stream of α particles travels with a constant energy of 20 MeV and carries a current of 2.5 μA. a) If the beam is directed perpendicular to a plane target, how many α's will strike this target in 8 seconds? b) At any given instant, how many α's are in a...

Homework Statement https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2112/summer/homework/Ch-21-Gauss-Law/charged_sheet/sheet.gif An infinite nonconducting sheet of charge, oriented perpendicular to the x-axis,passes through x = 0. It has area density σ1 = -3...

Yes, that looks correct.

The tensions actually don't need to be found. Once I had the correct torque equation, I substituted T1(sin39/sin52) in for T2, and the T1's cancel out completely, leaving you with only x to solve for.

Thank you both so much! You're both correct; the pivot point was the center of mass and I was including it in my calculations when I shouldn't have. Apparently even though I read that the pivot point was the center of mass, part of my internal being still wanted the center of mass at the...

Oops, sorry! I am solving for the distance x from the left side of the bar to its center of mass. Since the bar is of non-uniform density, the center of mass isn't at the center of the bar. (hopefully the picture below will show. I'm still learning how the posting works.)...

Homework Statement The bar is of nonuniform density so one end is heavier than the other. It has an overall length of 6.9 meters and is held in place by two very light wires. The left cord makes an angle with the wall of Θ = 39 degrees and the right cord makes an angle of Φ = 52 degrees...