Recent content by waterwalker10

Maybe this can be compared to how our jet streams are always changing. I haven't seen to many more photos that prove that these belts are changing but maybe... global warming? heh :biggrin:

OK, so I work for an organization that deals with "space" 24/7 and controls satellites. We had a discussion today on whether INNER/OUTER SPACE starts at 100Km above the Earth or where the atmosphere becomes a complete vacuum. NASA says 50 miles...ect... My opinion is that Inner Space can be...

Here is the image. BTW this is an old homework assignment that I never could figure out...any help is much appreciated. Thanks.

Willie took a soup can from the kitchen trash, added a handful of rusty ball bearings from the bottom of his Dad's junk drawer, and is now about to put it into the deep end of the family pool that Dad has just finished cleaning. Dad is not amused. "Don't worry," Willie says, "It'll float."...

Used SOH CAH TOA here... and got approx 56 degrees North of East. Hypo = 18.03 Adja = 10 Oppo = 15 sinA 15/18.03 = .832 = 56.299 cosA 10/18.03 = .555 = 56.315 tanA 15/10 = 1.5 = 56.31 Correct?

Another Magnitude and Direction of resultant force ? I'm having issues on the second question. I feel that I'm missing some information. Since the lines are perpendicular do I consider one force (10N) at 90 degrees North? And if this is the case then is the other force (15N) at __ degrees...

Here is what I came up with for the final answer! Hope this helps some in need... A = 2*1.06 / 462 = 2.12/.2116 = 10.018 ft/s/s 450knots(0.46) = 450 knots * 1.15mph/1knot * 1.47ftps/1mph * (0.46s) = 333.27 ft The plane traveled 333.27ft in .46 seconds.

The distance of the bottle is 3.5 ft or 1.06 meters. With Earth as a reference point for gravitational pull, the bottle would take 0.46 seconds to hit the deck. See referenced link. http://jersey.uoregon.edu/AverageVelocity/index.html

Was given this problem as a homework assignment but I would like to solve it...just need a push in the right direction. An airliner is cruising at a ground speed of 450 knots. A flight attendant, serving drinks, accidentally knocks a bottle off her cart. The distance from the top of the...

Excellent. I've been watching a few more lecture videos so they seem to be helping too. Thank you! Mark this one as solved!

So is this the correct way to write acceleration?

Then to find the acceleration of the bullet inside the barrel I would use the following formula. a = Δv/Δt= (vfinal - vinitial) / (tfinal - tinitial) Initial thought was to use 1030m/s which is the muzzle velocity given above. And .0033 is the time it takes the bullet to travel the length...

Well good to know I was on the right track. I understand mean as average and only average. If I wanted the middle I would take the length of the barrel and divide it by half to find the velocity at that point. When I was in my algebra class I was taught to simplify. I guess it isn't wrong...

As funny as this is...this is exactly how they plan and execute! To bad it will cost $900M ;)

So it would be fair to say that the bullet travels the length of the barrel in .0033 seconds. Solve for Avg Velocity... \bar{V} = \Deltad / \Deltat \bar{V} = 170cm/.0033 secs = 51515.15cm/s or 515.15m/s Would you have to change the time to correlate with cm and not meters...