Recent content by willydavidjr

Well, thanks for that kaworito...But I looked back from different options for the answer and I found your answer but without the negative sign. I think it is positive.

Your formula for the perpendicular component m \frac {v_perp}{r} doesn't match with mass x acceleration. How is that so?

Ok I'll try again. But it seems I already did what you said and didn't work. I think I am missing something here.

There is a word linear magnification in physics in terms of optical instruments. It is a unitless number that is the ratio of the height of the image and the height of the object. Additionally, I think you are talking about the angular magnification of the telescope for the magnifying power...

A uniform ladder with a mass of 10 kg leans against a vertical, smooth wall making an angle of 60 degrees with a smooth floor as shown in diagram ( I provided the website: www.geocities.com/willydavidjr/ladder.html ) A nail in the floor keeps the ladder from slipping while a man...

A ball is launched from the edge of a table which is 2.5 m high. The initial velocity of the ball is 5 m/s at an angle of 30 degrees above the horizontal or table. If the gravitational acceleration is 10 m/s^2 and value of cos 30 degrees is 0.86. a.)Calculate the flight time in seconds. b.)...

Two oblong pieces of plane glass are separated from each other by a thin sheet of cellophane and held together with rubber bands, as shown in figure(I provided a website for the figure below), where the amount of separation is much exaggerated. If you place a "sodium vapor lam" vertically above...

You mean I need to sum up the two initial kinetic energy and the two final kinetic energy and get their difference?

A proton source injects H(+) ions at low speed. A beam of protons (each having a rest mass 1.67*10^-27 kg) is moving in a circle of radius 80.0 cm between 2 circular flat electromagnets. If these electromagnets supply a force of 8.00*10^-13 N on each proton directed toward the center of...

But my question Dr. Brain is how can I compute for the ratio of the energy lost from the initial energy?:confused:

Techno you mean, if the energy in capacitor is 20 joules, the energy in the battery is 40 joules? Am I right?

energy=1/2q^2/c= 1/2C^2V... Can I ask, do you know what is the formula for the work done by the battery? Thanks.

I think the answer on number 5 is the same as in number 2. After the S2 is closed, the charge in Capacitor is still the same. We only need the capacitor value and the value of the battery, in short the answer is also 12 microCoulombs.

There are really factors affecting on conservation of energy because some goes off on this factor. Maybe they are absorbed by friction or something else. There must be an exception on the problem.

That would be definitely constant. Because on V=(nR)(P/T), the only value we need to consider here is P and T because it will be assume that they have the same number of n and R is constant also.