Recent content by Xile

1. With light from a gaseous discharge tube incident normally on a grating with slit separation 2.23 μm, sharp maxima for a certain wavelength of light are produced at angles θ = -17.1° and +17.1°. Compute the wavelength of the light in nanometers. 2. I thought this would work...

but wouldn't the Vx(t)^2 be in the numerator, same with Vy(t)^2

ah, that looks a lot better but i don't really understand how you got to there? it confuses me..

my mistake, but even so all i end up with is more variables and equations.

edit: that above equation is wrong and when i redid it its even more crazy with even mroe variables. i have the answer at the back of the book, its 8100:1 but i have no idea where it came from.

I spent a while on it, and seemed to end up with some weird looking equations. First i wrote an equation for both components of the velocity Vv = Uv - (9.8 + Vv^2 . 0.0000378).t ie (0.0000378.t)Vv^2+Vv+(9.8t-Uv)=0 and same process (0.0000378t)Vh^2+Vh-Uh=0 keeping in mind we have the initial...

1. In a shotput event, a 2kg shotput is launched from a height of 1.5m with an initial velocity of 8m/s at an angle 60degrees to the horizontal. The formula R=0.0000378.v^2 gives the force due to air resistance (R) where v is the instantaneous velocity. Find the ratio of the gravitational force...

Im not talking about a hollow sphere, because it has to have mass to have a gravitational pull, but if i assume there was a well that went to the Earth's core, i jumped in and made it to the bottom, would i be crushed under the force when i reach the middle? Also i don't see how Gauss's law can...

Energy is used loosely, because every physical thing has energy. Mass energy, anything that's moving has more energy then something that's not. E=mc^2 even the great einstein himself saw it, energy is directly proportional to mass, they are one in the same. Although it does take quite a lot of...

If F=GmM / d^2 Let's assume we're using it to measure the force between me and the earth, as i go further away the force on my decreases, what would happen if i could go right to the centre of the earth? would i be crushed under the force or what?

I know that when quarks move away from the centre of a particle the attraction force on them increases. How and why does this happen? What happens if using an extreme amount of energy you do move it away to a decent distance? If the force gets stronger as it moves away, is there any force when...