Collision of Uniform Smooth Spheres: Finding Coefficients of Restitution

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SUMMARY

The discussion revolves around the collision dynamics between two uniform smooth spheres, P and Q, with masses of 3m and m respectively. Sphere P moves with an initial speed of u, while sphere Q moves in the opposite direction with a speed of 2u. The coefficient of restitution (e) between the two spheres is established as 5/9. The analysis includes deriving expressions for the post-collision velocities v and w, and conditions under which the coefficient of restitution e' between sphere Q and a vertical wall exceeds 1/9.

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Help slove pls!:(

A uniform smooth sphere P,of mass 3m, is moving in a straight line with speed u on a smooth horizontal table.Another uniform smooth sphere Q, of mass and m and having the same radius as P, moving with speed 2u in the same straight line as P but in the opposite direction to P. The sphere P collides with the sphere Q directly. The velocities of P and Q after the collision are v and w respectively, measured in the direction of motion of P before the collision. The coefficient of restitution between P and Q is e.

a) Find an expression for v in terms of u and e.
b) Show that, if the direction of motion and P is changed by the collision, then e>1/3.
c) Find an expression for w in terms of u and e.

Following the collision with P, the sphere Q then collides with and rebounds from a vertical wall which is perpendicular to the direction of motion of Q. The coefficient of restitution between Q and the wall is e'

Given that e=5/9, and that P and Q collide again in the subsequent motion,
e) Show that e'>1/9
 
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