Sketching velocity graph from acceleration graph

AI Thread Summary
To sketch a velocity vs. time graph from an acceleration vs. time graph, the area under the acceleration curve represents the change in velocity. In the first third of the graph, where acceleration is increasing, the velocity is also increasing but at an increasing rate. The middle third shows constant acceleration, indicating that the velocity remains constant during this period. In the last third, where there is deceleration, the velocity decreases. Understanding these relationships is crucial for accurately depicting the velocity graph.
azn4lyf89
Messages
17
Reaction score
0
I know that the area under an acceleration vs. time graph is the velocity, but how do I use that information to sketch a velocity vs. time graph. Is the area considered the slope for the velocity graph? Also how is it possible for a car to be slowing down during the first half of the motion? Attached is a rough sketch of what the acceleration vs. time graph looks like.
 

Attachments

  • untitled.JPG
    untitled.JPG
    2 KB · Views: 538
Physics news on Phys.org
so on the first thrid of the graph there is constant acceleration so what does this tell you about the velocity?? the middle third there is no acceleration which implies the velocity must be the same. and the last third there is decceleration which implies what about the velocity??
 
azn4lyf89 said:
I know that the area under an acceleration vs. time graph is the velocity, but how do I use that information to sketch a velocity vs. time graph.
You need additional information, such as the initial speed.

Note that in this graph, the acceleration increases to a maximum value, stays at that value, then decreases to zero. (Acceleration is only constant in the middle portion of the graph.) If this graph is accurate, and the car starts from rest, the speed is increasing at all times. Is that what you meant to describe?
 
RoryP said:
so on the first thrid of the graph there is constant acceleration so what does this tell you about the velocity?? the middle third there is no acceleration which implies the velocity must be the same. and the last third there is decceleration which implies what about the velocity??

Actually, your wrong. The first third of the graph is an increasing acceleration. The second third is a constant acceleration, and the last third is a decreasing acceleration.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top