Help Me! Solving Maths Basics - Car in Water

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The discussion revolves around solving a physics problem involving a car falling from a quay into the water. The key points include using projectile motion equations to determine the time taken for the car to hit the water and its impact velocity. With the quay height of 5m and gravitational acceleration assumed at 10m/s², the time to impact is calculated to be approximately 1 second. The vertical speed upon hitting the water is determined to be 5m/s, while horizontal motion remains independent. Understanding the separation of horizontal and vertical components is crucial for accurately solving projectile motion problems.
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I know I am thick!

I know this sound stupid but my kid has brought his homework home and although I am OK at higher maths i seem to have lost the ability to do the basics! :eek:
Can anyone help with this...

A car leaves a quay and ends in the water 6m away from the foot of the quay. The quay is 5m above water level.

Q. What is the time taken for the car to hit the water? Hence determine the velocity with which it hits the quay.

Cheers
 
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is there a time component to where teh car splashed?
Its projectile motion. That you need to look up.

x=v_x0*t; x=6;
y=the acceleration formula with a=g...mmm can't remmeber but i think its
y+v_y0*t+g/2*t^2; y=5;

solve for v_x0, v_y0...and then do the pythagorean to get the speed. or if they want the velocity vector then your done.
 
The car falls vertically at the acceleration of gravity so the horizontal speed and distance of the car won't matter.

Assuming g=10m/s^2,
s = 5m, u = 0m/s, a = 10m/s^2, t = ?

s=ut + 0.5a(t^2)
t = sqrt (2s/a)
= 1s

therefore using v=s/t
v = 5m / 1s = 5m/s

Just keep in mind that projectiles have 2 separate speeds, the horizontal and the verticle and they don't mix up unless you want to find the resultant force.
 
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