How Do You Calculate the Variable Resistance for Optimal Battery Charging?

AI Thread Summary
To calculate the variable resistance R for optimal battery charging, the goal is to ensure 25 Watts is absorbed by the battery with a 10.5V element. The current through the battery is determined to be approximately 2.381 A. Using Kirchhoff's Voltage Law (KVL), the equation -13 + 0.02*i + iR + 0.035*i + 10.5 = 0 is established. The resistance R can be calculated by substituting the current value into the equation derived from KVL. The discussion emphasizes the importance of correctly factoring in the 0.035 ohm resistor in the calculations to achieve the desired power dissipation.
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Homework Statement


http://img2.freeimagehosting.net/uploads/bf073a5eb1.png
http://img2.freeimagehosting.net/uploads/bf073a5eb1.png

Determine the variable resistance R if the 25 Watts to be absorbed by the battery (0.035 ohm resistor and the 10.5 V element).

Homework Equations


V = IR
P = IV

The Attempt at a Solution



Well I did KVL clockwise current flow
-13 + 0.02*i + iR + 0.035*i + 10.5 = 0
2.5 = 0.02i + 0.035i + iR

Then factoring in 25W=10.5*i
i = 2.381 A which is close to the answer but doesn't factor in 0.035 and I'm not sure how to do it
 
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jesuslovesu said:

The Attempt at a Solution



Well I did KVL clockwise current flow
-13 + 0.02*i + iR + 0.035*i + 10.5 = 0
2.5 = 0.02i + 0.035i + iR

Then factoring in 25W=10.5*i
i = 2.381 A which is close to the answer but doesn't factor in 0.035 and I'm not sure how to do it

The question was to compute R such that you got 25 W dissipated in the 10.5V battery. You computed what the current through this battery must be. Now use that in the equation with i and R you wrote above
 
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