Average Output Voltage Vdc of Full Wave Rectifier

AI Thread Summary
The average output voltage (Vdc) of a full wave rectifier in bridge configuration is calculated as Vm/(pi), while the RMS voltage (Vrms) is Vm/2. This differs from the midpoint configuration, where Vdc is 2Vm/(pi) and Vrms is Vm/sqrt(2). The peak inverse voltage for the bridge configuration is Vm, compared to 2Vm for the midpoint. For further understanding, consulting the appendix of the National Semiconductor Audio Handbook is recommended for detailed insights on rectifiers and their performance.
McMurry
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Homework Statement



The Vdc of Full Wave Rectifier (with diode) with midpoint configuration has been found to be
2Vm/(pi) and Vrms = Vm/sqrt(2)

How about the Vdc and Vrms value for the full wave rectifier but with bridge configuration.
The difference is the the peak inverse voltage across the diode is Vm instead of 2Vm for midpoint configuration.

Therefore, for bridge configuration,
Vdc = Vm/(pi)
and
Vrms = Vm/2

Am I correct?

Thanks in advance.



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I recommend looking at the appendix of this old National Semiconductor Audio Handbook. It has a nice treatment of rectifiers, especially the voltage vs. load vs. filter performance.
 
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