Any technique or trick for finding the coefficient

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To find the coefficient of x^19 in the expression (x+x^2+x^3+x^4+x^5+x^6)^5, one effective approach is to rewrite the polynomial as a finite geometric series and then raise it to the fifth power. This transformation allows for the application of combinatorial techniques to determine how many ways terms can be selected from each of the five factors to achieve the desired exponent sum of 19. Generating functions can also be utilized to simplify the process of finding the coefficient. Ultimately, the problem can be approached as a combinatorics challenge, focusing on the distribution of terms across the brackets. Understanding these methods can significantly streamline the calculation of coefficients in polynomial expansions.
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any technique or "trick" for finding the coefficient

Here is the polynomial expression

(x+x^2+x^3+x^4+x^5+x^6)^5

Each x term is raised to ascending powers of 1.

The entire sum in the brackets is raised to the 5th power.

Does anyone have any "special trick" for finding the coefficient of the term which contains x^19?
 
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what about generating functions? there's another way to rewrite the finite geometric series inside the brackets, and that formula raised to the 5th power has another formula, and you can plug in the appropriate numbers to get the coefficient for x^19
 


Think about how would you write out the expansion normally? You would write out the 5 factors in 5 separate brackets (..)(..)(..)(..)(..), and pick a term from each bracket to form a term on the RHS. How many ways can you pick those terms differently to get the exponents adding to 19? It's now a combinatorics problem.
 
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