What is the wavelength of an object at rest according to de Broglie's equation?

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SUMMARY

According to de Broglie's equation, the wavelength of an object at rest (where velocity v=0) is not defined in conventional terms. The uncertainty principle indicates that a particle cannot have a precisely defined position and momentum simultaneously, leading to the conclusion that a stationary particle is best represented by a wave packet. This wave packet has an expectation value of momentum equal to zero and consists of waves with both positive and negative momentum values, forming a standing wave with maximum amplitude at the particle's most likely location.

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if de Broglie's equation: wavelength = h/(mv) works allways, then what is the wavelength of an object at rest (v=0) is it undefined or infinity or something?
 
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Because of the uncertainty principle, you can't have a wave function for a particle that is definitely exactly at rest, just as it can't have any other definite exact value of momentum (and velocity).

The best you can do for a "stationary" particle is a wave packet whose momentum has an expectation value of zero, and includes waves with both positive and negative values of momentum, in a range that is centered on zero. I suspect that such a wave packet would be a standing wave with maximum amplitude at the most likely location of the particle, and decreasing to zero in either direction so the width and the momentum range satisfy the uncertainty principle.
 

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