Relationship between f(x) and f(1/x)

  • Thread starter Thread starter Uranium235
  • Start date Start date
  • Tags Tags
    Relationship
AI Thread Summary
The discussion revolves around solving the equation 2f(x) - 3f(1/x) = x^2 to find f(2). Initial confusion arises regarding the relationship between f(x) and f(1/x), with attempts to substitute values leading to incorrect results. By substituting x = 1, it is determined that f(1) = -1, which helps in further calculations. Substituting x = 2 leads to a new equation involving f(2) and f(1/2). Ultimately, the participant successfully solves for f(2) after following the guidance provided.
Uranium235
Messages
13
Reaction score
0
Here's a problem that I am having difficulty doing:

Homework Statement


The question states:
if 2f(x)-3f(1/x)=x^2, determine f(2)

I am confused about the relationship between f(x) and f(1/x). My attempt right now consists of substituting y for f(x), 1/y for f(1/x) and 2 for the x in x^2 but i am quite sure that this is wrong since I do not get the answer that I was supposed to get (which is -7/4)
 
Physics news on Phys.org
There is no relationship between f(x) and f(1/x) other then what you get from 2f(x)-3f(1/x)=x^2. if y = f(x) then 1/y would be 1/f(x) and this is not equal to f(1/x)

You can try to substitute various values for x and see what you get

if x = 1 this tells you that 2f(1) - 3f(1) = 1 so f(1) = -1

if x=2 this tells you that 2f(2) - 3f(1/2) = 4

now try to find another equation with f(2) in it
 
Thank you very much for the quick response. I was able to go from where you left off and get the correct answer. :smile:
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Back
Top