jarednjames said:
Just a thought, a firehose is made of a strong material and is subjected to high pressure water being pumped through it. They use two people to control it. If they let the hose go, it swings wildly around.
Why wouldn't this be the case with the space hose? Unless the hose is kept perfectly vertical any lateral movement would result in this wild swinging motion. The higher the flow velocity in the hose, the worse the problem.
This works also with a garden hose and is the example how you usually explain to kids how rockets work - the momentum of the water leaving the hose creates a push back force on the nozzle and hose in reverse direction of the outflowing water (=backwards).
BUT If you put an steel plate 10cm upfront of the nozzel which is connected via steel wires to the nozzle and turn on the water the water and its momentum will be going circular from the hose and hence equal itself out. Then the firemen could hold the hose with a single hand (but it would be hard to put out the fire)
If you use a cone instead of a plate so that the water is reflected slightly backwards on the fir men - then besides that they get wet the hose will be pulled out of their fingers if the don't hold it properly.
Look at the 'design thoughts' slide - this is exactly what the diffusor on top should do - recovering some of the pressure of the outflowing air and changing its direction to blowing slightly downwards to get a pull on the hose instead of a push (and hold its own and the N-SAT weight too as an option). Even the famous bouncing ball in a fountain works that way by using the impact pressure to hold their own weight.
You can even use this pull force for erecting the hose and to stabilize the whole thing when upright. Such a downward blowing diffusor is the pneumatic replacement for the top counterweight suggested for a standard space elevator.
If the diffusor would be held vertical by a static pendulum mass underneath and the diffusor plate beeing not fixed (or a gyroscope - because the diffusor could be also a propeller mass rotating in the outflowing air and maybe even produce electricity). Then as soon as the hose bows to one side the diffusor plate will be lifted on this side and allows to blow out more gas on this side, which will then create a backword force moving it upright again until the momentum is balanced again.
The force which acts on a rocket is:
F=A*density*v²
Meaning if the hose would be very short then near the ground the force resulting out of the asumed possible flowspeed of 3,5m/s would be (if the blowdown area is equal to the hose area to prevent pressure/speed changes):
F=0,05*1,29*3.5²=0,79N - enough to balanace the weight of the suggested N-SAT
What scares me a little bit is that because of ideal gas law if the volume on the top should be is 625x higher and hence the density 625x lower (see one of my previous replies on this),
BUT because of continuity law this would mean that if the diameter of the hose is unchanged the air speed could be up to 625 times higher, meaning 3,5x625 which gives approximately 2200m/sec (30% of cosmic speed) ??
Because the force goes with the square of the speed this would mean that the theoretically available force on top from blowing downwards could be *625²/625=625x higher =493N - which would be sufficient to hold 50kg ?!
But changing the direction of the outflowing air to side/downwards also recovers some of the cinetic energy as pressure on the diffusor, so the exact calculation probably is not that simple
This is the reason why the slides say that at 100km the diffusor should blow down only slightly :-)
Put this probably would be question 3) - as soon as we have a decision on question 1) and because we also need to find out what 2) the friction does to the airflow.
gutemine