What is the Origin of the Friction Force in Surfer's Motion on a Wave?

AI Thread Summary
The discussion focuses on calculating the friction force acting on a surfer on a board inclined at 10º, accelerated by a wave at 1.0 m/s². The initial calculation suggests a friction force of 50N, but this value does not match the multiple-choice options provided. Another participant proposes a different approach, considering gravitational and inertial forces, leading to a friction force of approximately 188N. This discrepancy highlights the importance of correctly accounting for all forces in the system. The conversation emphasizes the need for precise calculations in physics problems involving motion on inclined surfaces.
Hernaner28
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Homework Statement


surf.jpg

The surfer (70kg) is standing over a board which has an angle of 10º with the horizontal. A wave acelerates him to the right at 1.0m/s^2. There is a force that prevents the surfer from sliding over the board.


Homework Equations


Calculate that force. What's the origin of this force?


The Attempt at a Solution



What I did was to analize the surfer only and since there's horizontal aceleration to the right then there's a wave force in horizontal direction to the right. So I just analized it in axis x given the faact that at axis y it doesn't move. So the equations:


http://eva.fing.edu.uy/filter/tex/pix.php/fa2415fb159333cacb5c7a42d79502d8.png
http://eva.fing.edu.uy/filter/tex/pix.php/093b650ee4c9116ddcd68135cf37b616.png

Then I calculated the weight at axis x:

http://eva.fing.edu.uy/filter/tex/pix.php/857f0c71f94a74d9cb6e58fc3e611cfe.png

So the friction force has to be the difference among these two and in the direction of the wave force and it would be 50N but the option is not in the moddle multiplechoice I'm doing.

Thanks!
 
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Hernaner28 said:

Homework Statement


surf.jpg

The surfer (70kg) is standing over a board which has an angle of 10º with the horizontal. A wave acelerates him to the right at 1.0m/s^2. There is a force that prevents the surfer from sliding over the board.


Homework Equations


Calculate that force. What's the origin of this force?


The Attempt at a Solution



What I did was to analize the surfer only and since there's horizontal aceleration to the right then there's a wave force in horizontal direction to the right. So I just analized it in axis x given the faact that at axis y it doesn't move. So the equations:


http://eva.fing.edu.uy/filter/tex/pix.php/fa2415fb159333cacb5c7a42d79502d8.png
http://eva.fing.edu.uy/filter/tex/pix.php/093b650ee4c9116ddcd68135cf37b616.png

Then I calculated the weight at axis x:

http://eva.fing.edu.uy/filter/tex/pix.php/857f0c71f94a74d9cb6e58fc3e611cfe.png

So the friction force has to be the difference among these two and in the direction of the wave force and it would be 50N but the option is not in the moddle multiplechoice I'm doing.

Thanks!


Hi, in my opinion the answer is the following: in the (accelerated) frame where the man is at rest the following forces act on the man: gravity (m g), inertial force (-m a), the reaction of the table which is perpendicular to the plane of the board (R) and and friction (F) which is parallel to the board; if you sum (vectorially of course) all these force you should obtain zero in order to say that the man is in equilibrium over the board; you have then two equations in two unknowns (F and R); solving the system I obtain

F=m(g sin(\theta) +a cos(\theta))

substituting \theta=10°, a=1\frac{m}{s^2}, m=70Kg, I obtain
F≈188N
 
Oh yes! You're right! I forgot that the inercial force is negative! Thanks!
 
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