Work with force changing with angle

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The discussion revolves around the formula for work done when a force is applied at an angle, specifically questioning whether the work should be calculated as MGcos²θ. Participants express concerns about the initial formulas and the setup of the problem, indicating potential miscalculations. There is also a mention of a specific physics problem from a textbook, highlighting the challenge of accessing various educational resources. The conversation emphasizes the importance of clarity in understanding the relationship between force, angle, and work. Accurate interpretation of physics formulas is crucial for solving related problems effectively.
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IF F=MGcos θ AND THE ANGLE BETWEEN F AND D IS θ
THEN WILL THE WORK BE MGcos2θ?
 
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MGDcos²θ, yes. But I'm a bit concerned about your formulas to begin with. What's the setup? You might be accounting for θ once more than you need to.
 
serway problem 7,20
 
I'm not sure why you assume we all have access to every textbook used for physics lectures.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...

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